class 11th physics notes
前往频道在 Telegram
Contact here at @PromoXtalk_bot for any business/ promotion related queries Contact here @MaterialXrequest_bot for requesting any Study materials
显示更多📈 Telegram 频道 class 11th physics notes 的分析概览
频道 class 11th physics notes (@class_11_physics_notes) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 15 141 名订阅者,在 教育 类别中位列第 13 443,并在 印度 地区排名第 28 833 位。
📊 受众指标与增长动态
自 невідомо 创建以来,项目保持高速增长,吸引了 15 141 名订阅者。
根据 10 六月, 2026 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 -305,过去 24 小时变化为 -9,整体触达仍然可观。
- 认证状态: 未认证
- 互动率 (ER): 平均受众互动率为 9.50%。内容发布后 24 小时内通常能获得 1.41% 的反应,占订阅者总量。
- 帖子覆盖: 每篇帖子平均可获得 1 438 次浏览,首日通常累积 213 次浏览。
- 互动与反馈: 受众积极参与,单帖平均反应数为 0。
- 主题关注点: 内容集中在 pdfs, 12th, physics, ravi10, ravkum0030 等核心主题上。
📝 描述与内容策略
作者将该频道定位为表达主观观点的平台:
“Contact here at @PromoXtalk_bot for any business/ promotion related queries
Contact here @MaterialXrequest_bot for requesting any Study materials”
凭借高频更新(最新数据采集于 11 六月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 教育 类别中的关键影响点。
15 141
订阅者
-924 小时
-647 天
-30530 天
帖子存档
15 137
➥ Laws of motion Handwritten notes
➥ Also check :-
@class_11_chemistry_notes
@cbse11bystudentshelper
15 137
💔 jo log avi tak SCHOLORSHIP k liye register nhi kiye ho jaldi se krlo , kuch din me registration close ho jayga
✅ TEST is available in ONLINE mode FROM HOME also from 1- 15 October
⭐️ Registration is FREE 🆓
🖥 Affiliate code is RAVKUM0030
📍 Student Pincode = your area pincode
🔗 Register here - https://docs.google.com/forms/d/e/1FAIpQLSdChTNj2osLrt3TUl4QfGVKyFpbqY8Q1OiCcRb0HyBv9RfIWg/viewform
👥 Hurry! Register fast it's free 🆓
15 137
🎉 Quiz Completed! 🏆
Thank you for participating in today's quiz! 📚
Download Premium study mateials in Free from acadpills.com/premium 📖
15 137
Which of the following remains constant in uniform circular motion?
15 137
The resultant of two vectors A and B is perpendicular to vector A and its magnitude is equal to half the magnitude of vector B. The angle between A and B is:
15 137
The centripetal acceleration of a particle moving in a circle of radius r with uniform speed v is:
15 137
The horizontal range of a projectile is maximum when the angle of projection is:
15 137
For a projectile, the angle between the velocity and the acceleration at the highest point is:
15 137
A particle is moving in a circle with uniform speed. Its motion is:
15 137
At the highest point of its trajectory, the velocity of a projectile is:
15 137
The path of a projectile in the absence of air resistance is a:
15 137
A train is travelling at a speed of 90 km/h. Brakes are applied so as to produce a uniform acceleration of -0.5 m/s^2. Find how far the train will go before it is brought to rest.
15 137
When can the distance covered by a body be equal to its displacement?
15 137
A particle starts its motion from rest under the action of a constant force. If the distance covered in the first 10 seconds is S1 and that covered in the first 20 seconds is S2, then:
15 137
A drunkard walking in a narrow lane takes 5 steps forward and 3 steps backward, followed again by 5 steps forward and 3 steps backward, and so on. Each step is 1 m long and requires 1 s. How long the drunkard takes to fall in a pit 13 m away from the start?
15 137
The position-time (x-t) graph for a particle in uniform motion is a:
15 137
A particle moves in a straight line with a constant acceleration. It changes its velocity from 10 m/s to 20 m/s while passing through a distance of 135 m in t seconds. The value of t is:
现已上线!2025 年 Telegram 研究 — 年度关键洞察 
