KEEP PRACTICING 🤓📚
前往频道在 Telegram
9 am= English mix (pre+ mains) 11-12=CA Quiz 12:30_3pm =Reasoning(pre+ Mains) 4=Banking Awareness(BA)Quiz 5 pm = Botquiz CA 6_7=High level Di and Word problem After 7 Pm English(Error Quiz) Contact :-
显示更多📈 Telegram 频道 KEEP PRACTICING 🤓📚 的分析概览
频道 KEEP PRACTICING 🤓📚 (@practice_mind) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 11 975 名订阅者，在 教育 类别中位列第 16 602，并在 印度 地区排名第 33 305 位。
📊 受众指标与增长动态
自 невідомо 创建以来，项目保持高速增长，吸引了 11 975 名订阅者。
根据 25 八月, 2026 的最新数据，频道保持稳定运转。过去 30 天订阅人数变化为 -149，过去 24 小时变化为 -2，整体触达仍然可观。
- 认证状态： 未认证
- 互动率 (ER)： 平均受众互动率为 7.78%。内容发布后 24 小时内通常能获得 3.61% 的反应，占订阅者总量。
- 帖子覆盖： 每篇帖子平均可获得 932 次浏览，首日通常累积 433 次浏览。
- 互动与反馈： 受众积极参与，单帖平均反应数为 1。
- 主题关注点： 内容集中在 kp10, exm, affair, maxm, ibps 等核心主题上。
📝 描述与内容策略
作者将该频道定位为表达主观观点的平台：
“9 am= English mix (pre+ mains)
11-12=CA Quiz
12:30_3pm =Reasoning(pre+ Mains)
4=Banking Awareness(BA)Quiz
5 pm = Botquiz CA
6_7=High level Di and Word problem
After 7 Pm English(Error Quiz)
Contact :-”
凭借高频更新（最新数据采集于 26 八月, 2026），频道始终保持新鲜度与高覆盖。分析显示受众积极互动，使其成为 教育 类别中的关键影响点。
11 975
订阅者
-224 小时
-267 天
-14930 天
数据加载中...
吸引订阅者
八月 '26
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一月 '23
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十二月 '22
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+285
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三月 '22
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二月 '22
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一月 '22
+365
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十二月 '21
+518
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十一月 '21
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十月 '21
+720
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九月 '21
+539
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八月 '21
+958
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七月 '21
+1 369
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六月 '21
+1 111
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+1 346
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四月 '21
+869
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三月 '21
+383
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二月 '21
+402
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一月 '21
+836
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十二月 '20
+9 651
在0个频道中
| 日期 | 订阅者增长 | 提及 | 频道 | |
| 27 八月 | +1 | |||
| 26 八月 | 0 | |||
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| 03 八月 | +1 | |||
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| 01 八月 | 0 |
频道帖子
📌SBI JA Registration UPDATE 💥
REG. :- 801228 (Till Now )
Last Date:- 31 Aug
Apply:- https://ibpsreg.ibps.in/sbijajul26/
| 2 | 📌SBI JA Registration UPDATE 💥
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| 3 | ₹146 📖Guidely Descriptive Writing Test For SBI PO 2026👌 IBPS PO 2026
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| 4 | Part 1: Profit & Loss Practice Questions
Q1. A shopkeeper bought an article for ₹800. He marked it up by 40\% above its cost price and offered a discount of 20\% on the marked price. Find his net profit percentage.
Q2. The cost price of 15 items is equal to the selling price of 12 items. Find the profit percentage made by the seller.
Q3. An article is sold at a profit of 15\%. If both the cost price and selling price are reduced by ₹200, the profit percentage becomes 20\%. Find the original cost price of the article.
Q4. A shopkeeper allows two successive discounts of 10\% and 20\% on an article. If the final selling price of the article is ₹576, find the marked price of the article.
Q5. A dishonest dealer sells goods at cost price but uses a false weight of 900\text{ g} instead of 1\text{ kg}. Find his actual profit percentage.
Q6. The cost price of article A is 25\% more than the cost price of article B. Article A is sold at a profit of 20\% and article B is sold at a loss of 10\%. If the total profit earned on both articles together is ₹105, find the cost price of article B.
Q7. A person sold two items for ₹4,800 each. On one item, he gained 20\% and on the other, he lost 20\%. Find his overall profit or loss amount in rupees.
Q8. A trader marks his goods 50\% above the cost price and allows a discount of x\%. If he still makes a profit of 20\%, find the value of x.
Q9. If an article is sold for ₹1,380, the loss percentage is equal to the profit percentage gained when the same article is sold for ₹1,620. Find the cost price of the article.
Q10. The ratio of the marked price to the cost price of an item is 5 : 4. If a discount of ₹150 is given on the marked price, the shopkeeper earns a profit of 10\%. Find the cost price of the item.
Part 1 Solutions: Profit & Loss
S1.
* * * * S2.
* Given: 15 \times CP = 12 \times SP \implies \frac{SP}{CP} = \frac{15}{12} = \frac{5}{4}
* S3.
* Let initial CP = x. Then initial SP = 1.15x.
* New CP = x - 200, New SP = 1.15x - 200.
* New profit is 20\%:
S4.
* Let Marked Price be MP.
* Single equivalent multiplier after 10\% and 20\% discount = 0.90 \times 0.80 = 0.72
* S5.
* Formula: \text{Profit \%} = \frac{\text{Error}}{\text{True Value} - \text{Error}} \times 100
* Error = 1000\text{ g} - 900\text{ g} = 100\text{ g}
* S6.
* Let CP_B = 100x. Then CP_A = 125x.
* Profit on A = 20\% \text{ of } 125x = 25x
* Loss on B = 10\% \text{ of } 100x = 10x
* Net Profit = 25x - 10x = 15x
* Given 15x = 105 \implies x = 7
* S7.
* * * Total CP = 4000 + 6000 = \text{₹}10,000
* Total SP = 4800 + 4800 = \text{₹}9,600
* Overall Loss = 10000 - 9600 = \mathbf{\text{₹}400 \text{ Loss}}
S8.
* Let CP = 100. Then MP = 150.
* Since profit is 20\%, SP = 120.
* Discount = MP - SP = 150 - 120 = 30
* Discount \% (x) = \frac{30}{150} \times 100 = \mathbf{20\%}
S9.
* Since Loss \% at ₹1,380 = Profit \% at ₹1,620:
S10.
* Let CP = 4x and MP = 5x.
* * Discount = MP - SP = 5x - 4.4x = 0.6x
* Given discount = 150 \implies 0.6x = 150 \implies x = 250
* Part 2: Mixture & Alligation Practice Questions
Q11. In what ratio must a grocer mix two varieties of pulses costing ₹60 per kg and ₹85 per kg so that the resulting mixture is worth ₹70 per kg?
Q12. A container contains 80\text{ liters} of pure milk. 16\text{ liters} of milk is taken out and replaced with water. This process is repeated one more time. Find the final quantity of pure milk remaining in the container.
Q13. A mixture of 60\text{ liters} contains milk and water in the ratio 3 : 2. How much water should be added to this mixture so that the ratio of milk to water becomes 6 : 5?
Q14. In Vessel A, milk and water are mixed in the ratio 4 : 1, and in Vessel B, they are in the ratio 3 : 2. In what ratio should liquid from Vessel A and Vessel B be mixed to form a new mixture containing milk and water in the ratio 7 : 3?
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| 13 | 📌 IBPS PO Prelims Exam Analysis 2026
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