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Option: C) (-2, 3, 0, 1) โœ…โœ… ๐Ÿ”ฅ Explanation: 1. The variables are initialized as follows: i = -3; j = 2; k = 0; m; //is uninitialized 2. The expression ++i increments the value of i by i, so now i is -2. 3. The expression ++j increments the value of j by 1, so now j is 3. 4. The expression ++k is not evaluated because of the short-circuiting property of the logical OR (||) operator. 5. The expression ++i && ++j is evaluated as follows: a. ++i has a value of -2, which is non-zero, so the expression evaluates to true. b. Since the left-hand side of the logical AND (&&) operator is true, the right-hand side is evaluated. c. ++j has a value of 3, which is non-zero, so the expression evaluates to true. 6. The expression ++i && ++j || ++k is evaluated as follows: a. The left-hand side of the logical OR (||) operator (++i && ++j) is true, so the right-hand side is not evaluated because of the short-circuiting property of the logical OR operator. b. The value of the expression ++i && ++j is 1, which is assigned to m. 7. The final values of the variables are: i = -2 j = 3 k = 0 m = 1 Finally output of the program is: -2, 3, 0, 1

๐Ÿ”ฅOption- A)
-2, 3, 1, 1
โœ“ *โœจExplanation:* *#STEP-1:* This code snippet is declares four variables i, j, k, and m of type integer, and initialized i = -3, j = 2, and k = 0. *#STEP-02:* The expression ++i && ++j && ++k is evaluated and the result is assigned to m. *#STEP-03:* The ++ operator(pre-Increment) increments the value of the variable by 1. In this expression, i is incremented to -2, j is incremented to 3, and k is incremented to 1. *#STEP-04:* The && operator is a logical AND operator, which returns 1 if both of its operands are non-zero, and 0 otherwise. *#STEP-05:* In this case, since all the operands are non-zero, the expression evaluates to 1 and the value 1 is assigned to m. *#STEP-06:* Finally, the printf function is called to print the values of i, j, k, and m. So, the output of this program will be:
-2, 3, 1, 1
*Note:* that the value of i is -2 because it was incremented by the ++ operator before the expression was evaluated. Join for more: T.me/CseHackTech Happy Learning๐Ÿ˜

#Options: What will be the output of the program?
Anonymous voting