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Zoho Coding output 23-05-2021 Q1: 0 Q2: -4 Q3:11 Q4: -49 Q5: 33 Q6: 10 Q7: 47

Appitude 30 400 meter 1104 511 There is no loss or gain. 1000 4.8 min 100 degree 5 Monday 4 minutes 3km 6 centimetres 153600 2hr30 min 16 12 552

BE/B.Tech 2021 MINDTREE 2021 off-campus registrations are open. Please circulate it with your students who are interested. They can directly register. https://www.mindtree.com/careers/campus-careers The JD containing CTC, T&C is present on the above link itself. Link to register is also present in the above link. Registration link will be open till May 24th, 9:00 AM.

Technical Ability - Missing term - I Missing term - 78 HIVP Odd number - 7 49 Choose Pair - 14 28 20 members of cube - 19 Find the pairs - 3,6 If X=6 - 646 Choose odd pair - 36,126 Odd pair -36,126 44,55-100 C3X,F6U-L120 Wrong term- GUL If 232 : - 1728 Select the Pair - Horizontal Vertical Incorrect term - 729 If a System Code - 2520 Incorrect - 45 Ans - Tamilnadu Chnnai Missing term - u82a Odd pair - 24 72 A College - 1/5 Ans - DFI HLQ Ans - AIIC Ans - Hate Despise MNOP:OLQN Incorrect - 252 City Village - 31254 Arrange - 54321 Arrange - 45321 ( Country) Ans - HMRX Ans - SUOQ

Odd pair -36,126 @placementupdatess 44,55--100 C3X,F6U-- L120 Pair of numbers-3,6 Wrong term- GUL Odd number--7,49 @placementupdatess Missing term-21

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2020 or 2021 batch pass out can apply An engineering degree B.E/B.Tech/MCA/M.Tech/M.Sc or any Equivalent Degree. 0 - 1 Years of Experience. Job location pune

NICE_PERMUTATIONS PYTHON from itertools import permutations as p n=int(input()) if n<4: print(0) else: l=[i for i in range(1,n+1)] s=list(p(l)) res=[] for k in s: rem=[] for j in k: rem.append(j%2) if rem[0]!=rem[1] or rem[-1]!=rem[-2]: continue c=1 for i in range(1,len(rem)-1): if rem[i]==rem[i-1] or rem[i]==rem[i+1]: continue else: c=0 break if c: res.append(k) print(len(res)%((10**9)+7)) @placementupdatess

HACKWITHINFY SOLUTIONS #MAKE STRING EQUAL #PYTHON res=0 def equal(s,n): global res k=list(s) while len(k)!=n: k.pop(0) res+=1 return ''.join(k) a=input() b=input() c=input() s=len(a)+len(b)+len(c) m=min(len(a),len(b),len(c)) if len(a)>m: a=equal(a,m) if len(b)>m: b=equal(b,m) if len(c)>m: c=equal(c,m) if a==b==c: print(res) else: print(s) @placementupdatess

def findTrailingZeros(n):    count = 0  while(n >= 5):         n //= 5      count += n    return count  n = 100 print("Count of trailing 0s " + "in 100! is", findTrailingZeros(n))