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Pure Mathematical Academy

Pure Mathematical Academy

前往频道在 Telegram

Contact Us @PMAofficial20 YouTube Channel link for Solution https://youtube.com/channel/UCY5qGWuYe46ajwxwWNO1DlQ Facebook Page joining link https://bit.ly/3AAjl1j Telegram Shorts Channel https://t.me/pmashortscsir21

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📈 Telegram 频道 Pure Mathematical Academy 的分析概览

频道 Pure Mathematical Academy (@puremathcsir2021) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 10 911 名订阅者,在 教育 类别中位列第 18 470,并在 印度 地区排名第 34 666 位。

📊 受众指标与增长动态

自 невідомо 创建以来,项目保持高速增长,吸引了 10 911 名订阅者。

根据 10 十一月, 2026 的最新数据,频道保持稳定运转。过去 30 天订阅人数变化为 91,过去 24 小时变化为 -2,整体触达仍然可观。

  • 认证状态: 未认证
  • 互动率 (ER): 平均受众互动率为 15.93%。内容发布后 24 小时内通常能获得 4.27% 的反应,占订阅者总量。
  • 帖子覆盖: 每篇帖子平均可获得 1 738 次浏览,首日通常累积 466 次浏览。
  • 互动与反馈: 受众积极参与,单帖平均反应数为 3。
  • 主题关注点: 内容集中在 algebra, iit, pyq, dec, jrf 等核心主题上。

📝 描述与内容策略

作者将该频道定位为表达主观观点的平台:
“Contact Us @PMAofficial20 YouTube Channel link for Solution https://youtube.com/channel/UCY5qGWuYe46ajwxwWNO1DlQ Facebook Page joining link https://bit.ly/3AAjl1j Telegram Shorts Channel https://t.me/pmashortscsir21”

凭借高频更新(最新数据采集于 11 十一月, 2026),频道始终保持新鲜度与高覆盖。分析显示受众积极互动,使其成为 教育 类别中的关键影响点。

10 911
订阅者
-224 小时
-37 天
+9130 天
帖子存档
⚠️Last Offer on CSIR NET DEC 2026 existing Courses 🚨Offer Ends Soon.....
⚠️Last Offer on CSIR NET DEC 2026 existing Courses 🚨Offer Ends Soon.....

✨️Diwali Dhamaka Offer🪔 ⚠️ Last Offer in All CSIR NET Dec 2026 Batches
✨️Diwali Dhamaka Offer🪔 ⚠️ Last Offer in All CSIR NET Dec 2026 Batches

📣 WE ARE HIRING! Are you passionate about Mathematics? Do you love teaching and inspiring students? Pure Mathematical Academ
📣 WE ARE HIRING! Are you passionate about Mathematics? Do you love teaching and inspiring students? Pure Mathematical Academy is looking for dedicated Mathematics Teachers to join our academic team! The minimum eligibility is CSIR NET Qualified. 🚨Apply before 12th November 2026. Fill Application Form:: https://forms.gle/d8h3EA2YkCPLkVDy5 Join Pure Mathematical Academy. Let's teach. Let's inspire. Let's excel!

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CSIR_NET_June_2025_Questions_with_Answer_Key_Pure_Mathematical_Academy.pdf9.50 KB

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CSIR_NET_Dec_2024_Assam_Centre_with_Answer_Key_Mathematics_Pure.pdf9.01 KB

Are You Ready !?
Are You Ready !?

👆 Answer Key :: A Solution is now available. If you need you may check our YouTube Channel.

🔥Fire Problem by CSIR NET June 2026 - Real Analysis 😵‍💫Very Interesting Problem
🔥Fire Problem by CSIR NET June 2026 - Real Analysis 😵‍💫Very Interesting Problem

⚠️Very Important Notice about Our Courses
⚠️Very Important Notice about Our Courses

👆 Answer Key :: B,D Solution is now available. If you need you may check our YouTube Channel.

#IIT JAM 2026 Topic : Linear Algebra Join🔜@puremathcsir2021 Join🔜@pmashortscsir21 Solution will be available Today at 7 pm
#IIT JAM 2026 Topic : Linear Algebra Join🔜@puremathcsir2021 Join🔜@pmashortscsir21 Solution will be available Today at 7 pm on our YouTube Channel.

👆 Answer Key :: B,C,D Solution is now available. If you need you may check our YouTube Channel.

#CSIR NET June 2026 Topic : Linear Algebra Join🔜@puremathcsir2021 Join🔜@pmashortscsir21 Solution will be available Today at
#CSIR NET June 2026 Topic : Linear Algebra Join🔜@puremathcsir2021 Join🔜@pmashortscsir21 Solution will be available Today at 7 pm on our YouTube Channel.

👆 Answer Key :: 0.25 Solution is now available. If you need you may check our YouTube Channel.

#IIT JAM 2026 Topic : Real Analysis Join🔜@puremathcsir2021 Join🔜@pmashortscsir21 Solution will be available Today at 7 pm o
#IIT JAM 2026 Topic : Real Analysis Join🔜@puremathcsir2021 Join🔜@pmashortscsir21 Solution will be available Today at 7 pm on our YouTube Channel.

🚀 Green's Function 🔥 One SHOT - ODE Hot Concept ✅ Available https://youtube.com/@puremathcsir2021?si=fyRHI2kBkL7alE4K
🚀 Green's Function 🔥 One SHOT - ODE Hot Concept ✅ Available https://youtube.com/@puremathcsir2021?si=fyRHI2kBkL7alE4K

⚠️Don't Wait for Last Date Complete your application early to avoid delays. Need Help with Your Application? CSIR-NET Helpdes
⚠️Don't Wait for Last Date Complete your application early to avoid delays. Need Help with Your Application? CSIR-NET Helpdesk: csirnet@nta.ac.in Helpline Numbers: 011-40759000 / 011-69227700 Click Here to visit :: csirnet.nta.nic.in #CSIRNET #NTAUpdate #NTAExams #CSIRUGCNET #UGCNETDecember2026 #puremathematicalacademy

👆 Answer Key :: B,C Solution is now available. If you need you may check our YouTube Channel.