SuperCoaching AE/JE by Testbook
前往频道在 Telegram
Here you’ll get all PDFs & latest update for your AE/JE exams ✅ Join SuperCoaching AE/JE -Electrical: https://testbook.com/ae-je-electrical-coaching Civil: https://testbook.com/ae-je-civil-coaching Mechanical:https://testbook.com/ae-je-mechanical-coaching
显示更多📈 Telegram 频道 SuperCoaching AE/JE by Testbook 的分析概览
频道 SuperCoaching AE/JE by Testbook (@testbookengineering) 英语 语言赛道中的 是活跃参与者。目前社区聚集了 37 691 名订阅者，在 教育 类别中位列第 5 009，并在 印度 地区排名第 10 129 位。
📊 受众指标与增长动态
自 невідомо 创建以来，项目保持高速增长，吸引了 37 691 名订阅者。
根据 11 十一月, 2026 的最新数据，频道保持稳定运转。过去 30 天订阅人数变化为 1 506，过去 24 小时变化为 -16，整体触达仍然可观。
- 认证状态： 未认证
- 互动率 (ER)： 平均受众互动率为 8.72%。内容发布后 24 小时内通常能获得 3.94% 的反应，占订阅者总量。
- 帖子覆盖： 每篇帖子平均可获得 3 288 次浏览，首日通常累积 1 484 次浏览。
- 互动与反馈： 受众积极参与，单帖平均反应数为 2。
- 主题关注点： 内容集中在 sir, ssc, rrb, aman, upsssc 等核心主题上。
📝 描述与内容策略
作者将该频道定位为表达主观观点的平台：
“Here you’ll get all PDFs & latest update for your AE/JE exams
✅ Join SuperCoaching AE/JE
-Electrical: https://testbook.com/ae-je-electrical-coaching
Civil: https://testbook.com/ae-je-civil-coaching
Mechanical:https://testbook.com/ae-je-mechanical-coa...”
凭借高频更新（最新数据采集于 12 十一月, 2026），频道始终保持新鲜度与高覆盖。分析显示受众积极互动，使其成为 教育 类别中的关键影响点。
37 691
订阅者
-1624 小时
-697 天
+1 50630 天
帖子存档
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A particle executes simple harmonic motion with amplitude A and angular frequency omega. What is the ratio of its maximum kinetic energy to its maximum potential energy?
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A thin uniform rod of length L and mass M is pivoted at one end and released from a horizontal position. What is the magnitude of the angular acceleration of the rod immediately after it is released?
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A particle of mass m moves in a 1D potential V(x) = k|x|. If the particle is in the nth energy level according to the WKB approximation, what is the dependence of energy E_n on the quantum number n?
If the roots of the quadratic equation x^2 - kx + 16 = 0 are equal, then the value of k is:
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A particle of mass m moves in a potential V(x) = k|x|, where k is a constant. If the particle oscillates with energy E, what is the dependence of the oscillation period T on the energy E?
A particle of mass m moves in a potential V(x) = k|x|^n. For the energy E to be proportional to the frequency of oscillation f, what must be the value of n?
A particle of mass m moves in a potential V(x) = k|x|^n. For a total energy E, how does the time period T of oscillation scale with E?
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If f(x) is a polynomial such that f(x)f(1/x) = f(x) + f(1/x) and f(2) = 9, what is the value of f(3)?
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