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def solve(N):
sum_needed = (N * (N + 1)) // 2
k = ((N + 1) * (N + 2)) // 2
count = 0
total = 0
for i in range(N + 1, 0, -1):
if total >= sum_needed:
break
total += i
count += 1
return count
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现已上线!2025 年 Telegram 研究 — 年度关键洞察 
