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Class 10th Maths notes

Class 10th Maths notes

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The HCF of 91 and 114 is:
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The HCF of 65 and 117 is expressible in the form 65m - 117, where m is an integer. The value of m is:
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The smallest number that is divisible by all numbers from 1 to 10 (both inclusive) is:
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The product of two numbers is 306 and their HCF is 6. The LCM of the numbers is:
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The decimal expansion of 22/7 is:
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The LCM of two numbers is 18 and their HCF is 3. If one of the numbers is 9, then the other number is:
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The values of the remainder r, when a positive integer a is divided by 3 are
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For any two positive integers a and b, HCF (a, b) × LCM (a, b) =
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n² – 1 is divisible by 8, if n is
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The prime factorisation of 96 is
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If the HCF of 65 and 117 is expressible in the form 65m – 117, then the value of m is
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Using Euclid’s division algorithm, the HCF of 231 and 396 is
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For some integer m, every even integer is of the form
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Euclid’s division lemma states that for two positive integers a and b, there exist unique integers q and r such that a = bq + r, where r must satisfy
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The decimal expansion of the rational number 23/(22 . 5) will terminate after
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The sum or difference of two irrational numbers is always
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The least number that is divisible by all the numbers from 1 to 5 is:
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The largest number that divides 70 and 125, which leaves the remainders 5 and 8, is:
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