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def processExecution(power, minPower, maxPower):     result = []     for min_p, max_p in zip(minPower, maxPower):         count = sum(1 for p in power if min_p <= p <= max_p)         power_sum = sum(p for p in power if min_p <= p <= max_p)         result.append((count, power_sum))     return result Amazon

#include <iostream> #include <vector> #include <string> using namespace std; int count_vowels(string str) {     int count = 0;     string vowels = "aeiou";     for (char ch : str) {         if (vowels.find(tolower(ch)) != string::npos) {             count++;         }     }     return count; } vector<string> determine_winner(vector<string> strings) {     vector<string> winners;     for (string str : strings) {         if (count_vowels(str) == 0) {             winners.push_back("Chris");         } else {             winners.push_back("Alex");         }     }     return winners; }.  System and Strings JPMC Telegram:- @allcoding1

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#include <iostream> #include <vector> #include <algorithm> int getPotentialOfWinner(std::vector<int>& potential, long long k) {     int n = potential.size();     int x = potential[0];     int m = 0;     for (int i = 1; i < n; i++) {         if (m != k) {             if (x > potential[i]) {                 m++;             } else {                 x = potential[i];                 m = 1;             }         }     }     return x; } int main() {     std::vector<int> potentials = {3, 2, 1, 4};     long long k = 2;     std::cout << getPotentialOfWinner(potentials, k) << std::endl;     return 0; } Potential winner code Telegram:- @allcoding1

import heapq def reduce_sum(lst):     heapq.heapify(lst)     s = 0     while len(lst) > 1:         first = heapq.heappop(lst)         second = heapq.heappop(lst)         s += first + second         heapq.heappush(lst, first + second)     return s Reduce the Array

#include <iostream> #include <vector> #include <set> using namespace std; int getSmallestArea(vector<vector<int>>& grid) {     int rows = grid.size();     if (rows == 0) return 0;     int cols = grid[0].size();     if (cols == 0) return 0;     set<int> rowsSet, colsSet;     for (int i = 0; i < rows; ++i) {         for (int j = 0; j < cols; ++j) {             if (grid[i][j] == 1) {                 rowsSet.insert(i);                 colsSet.insert(j);             }         }     }     int width = colsSet.empty() ? 0 : *colsSet.rbegin() - *colsSet.begin() + 1;     int height = rowsSet.empty() ? 0 : *rowsSet.rbegin() - *rowsSet.begin() + 1;     return width * height; }  shipping space Salesforce

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MOD = 10**9 + 7 def solve(arrival_departure):     arrival_departure.sort(key=lambda x: x[1])     prev_departure = -1     total_stations = 0     for arrival, departure in arrival_departure:         if arrival > prev_departure:             total_stations += 1             prev_departure = departure     return total_stations % MOD def main():     N = int(input())     arrival_departure = []     for _ in range(N):         arrival, departure = map(int, input().split())         arrival_departure.append((arrival, departure))         result = solve(arrival_departure)     print(result) if name == "main":     main() Trains Code Python HackWithInfy Telegram:- @allcoding1

#include <iostream> #include <vector> #include <algorithm> using namespace std; const int MOD = 1e9 + 7; int main() {     int N, Q;     cin >> N;     vector<int> A(N);     for (int i = 0; i < N; ++i) {         cin >> A[i];     }     cin >> Q;     long long sum = 0;     for (int q = 0; q < Q; ++q) {         int type, L, R, X, i , zero1 , zero2;         cin >> type;         if (type == 1) {             cin >> L >> R >> X;             for (int j = L-1; j < R; ++j) {                 A[j] = min(A[j], X);             }         } else if (type == 2) {                         cin >> i >> zero1 >>zero2;             sum = (sum + A[i - 1]) % MOD;         }     }     cout << sum << endl;     return 0; } Replace by Minimum Code C++ HackWithInfy Telegram:- @allcoding1

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#include <iostream> #include <vector> #include <unordered_map> const int MOD = 1000000007; int n, m, startRow, startColumn, moves, q; std::vector<std::vector<int>&gt; obstacles; bool isObstacle(int x, int y) { for (auto&amp; obstacle : obstacles) { if (obstacle[0] == x &amp;&amp; obstacle[1] == y) { return true; } } return false; } int countPaths(int x, int y, int movesLeft, std::unordered_map<std::string, int="">&amp; dp) { if (x &lt; 0 y &lt; 0 x &gt;= n || y &gt;= m) { return 1; } if (movesLeft == 0 || isObstacle(x, y)) { return 0; } std::string key = std::to_string(x) + ":" + std::to_string(y) + ":" + std::to_string(movesLeft); if (dp.find(key) != dp.end()) { return dp[key]; } int paths = countPaths(x + 1, y, movesLeft - 1, dp) % MOD; paths = (paths + countPaths(x - 1, y, movesLeft - 1, dp)) % MOD; paths = (paths + countPaths(x, y + 1, movesLeft - 1, dp)) % MOD; paths = (paths + countPaths(x, y - 1, movesLeft - 1, dp)) % MOD; dp[key] = paths; return paths; } int main() { std::cin &gt;&gt; n &gt;&gt; m &gt;&gt; startRow &gt;&gt; startColumn &gt;&gt; moves &gt;&gt; q; obstacles.resize(q, std::vector<int>(2)); for (int i = 0; i &lt; q; ++i) { std::cin &gt;&gt; obstacles[i][0] &gt;&gt; obstacles[i][1]; } std::unordered_map<std::string, int=""> dp; int totalPaths = countPaths(startRow, startColumn, moves, dp); std::cout &lt;&lt; totalPaths &lt;&lt; std::endl; return 0; } C++ In a town called Gridland, there lived a man named Alex who had a special skill. He could move around a grid like a big square map. The grid had obstacles, things he couldn't go through. The grid is described by its size n x m, and Alex starts at a specífic position [startRow, startColumn). There are also obstacles in fixed positions. HackWithInfy @allcoding1