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WALKIN DRIVES ------------------------------------- Tech Mahindra is conducting WALK-IN DRIVE Role  : Customer Service (Inbound Voice Experience:  0-5 years Contact : Prajakta ( 09324344438 ) Email  : Prajakta.AnandKadam@TechMahindra.com Date : 21st December – 30 December Time : 9.30 AM – 4.00 PM Location: 4V7V+MMM, Wing – I & II, Oberoi Garden Estate,Off.Saki Vihar Road, Chandivali, Andheri (Ea, Andheri East, Mumbai, Maharashtra 400072 --------------------------------------- Tech Mahindra is conducting WALK-IN DRIVE Role : Non Voice Process Experience  : 0-1 years Date : 20th December – 29 December  Time : 9.30 AM – 12.00 PM Contact  : Khasim or Venu ( 8686369656 ) Location: Special Economic Zone, Tower – I, Plot No. 22 to, 34, Tech Mahindra SEZ Rd, Jubilee Enclave, Madhapur, Telangana 500081 ---------------------------------- Tech Mahindra is conducting WALK-IN DRIVE Role : Voice Process Experience  : 0-3 years Contact  : Jyoti Yadav ( 9667136104 ) Date : 20th December – 26 December  Time  : 9.30 AM – 5.30 PM Location : Tech Mahindra, B-19, Sector-62, Noida (OPP to DME college) -------------------------------------- AU Small Finance Bank is conducting WALK-IN DRIVE Role : Bank Officer  Experience  : 1-6years Contact : Madhu Sudan ( 8288868233 ) Date : 19th December – 28 December Time : 10.00 AM – 2.00 PM 1st Floor, Raksha Business Centre, Ambala Chandigarh Expy, Zirakpur, opposite BYJU’S Tuition Centre – Zirakpur ------------------------------------------ Kotak Mahindra is conducting WALK-IN DRIVE Role : CASA – Acquisition Manager Experience  : 2-4 years Contact : HR Dinesh M / John – 7022284825 Date : 19th December – 28 December  Time : 11.00 AM – 2.00 PM Location  : Kotak Mahindra Bank, #22, MG road, Next to trinity Metro station, Bangalore-01 --------------------------------------- Genpact is conducting WALK-IN DRIVE Role : Domestic Technical Support Voice Experience : 0 to 3 years Date : 26th December Time  : 11 am to 12 pm Location  : Genpact Plot No. 14/45, IDA Uppal, Habsiguda, Hyderabad 500079 ---------------------------------------- People group is conducting WALK-IN DRIVE Role : HNI Telesales Executive Experience  : 2 – 7 years Contact  : Simran ( 9833601383 ) Date : 18th December – 27 December Time : 9.30 AM – 5.30 PM Location  : Marwah Centre, 4th Floor, A & B Wing, Krishanlal Marwah Marg, Sakinaka Andheri East, Mumbai, Maharashtra 400072 ------------------------------------------ PARAS HEALTHCARE is conducting WALK-IN DRIVE Role : Marketing Executive Experience  : 1 – 6 years Contact  : RAJAN TRIVEDI ( 8141268743 ) Email : rajan.trivedi@parashospitals.com Date : 20th December – 29 December Time : 9.30 AM – 5.00 PM Location  : PARAS HEALTH CARE PVT LTD, Plot No, 1, JK Lane, Shobhagpura, Udaipur, Rajasthan 313001 @allcoding1_official ------------------------------------------- IndiGo is conducting WALK-IN DRIVE Role : Cabin Attendant Qualification  : 12th pass and above Experience  : Freshers Date : 26-Dec Time : 9am-12pm  Location  : The Centurion Hotel Shivajinagar, Opposite Akashwani, Narveer Tanaji Wadi, Pune, Maharashtra 411005 ----------------------------------------- Infosys is conducting WALK-IN DRIVE Role: Process Specialist Experience  : 1 to 3 years Send email and conform date of DRIVE in Email id : pooja.lalbage@infosys.com Location : Bangalore WALK-IN DRIVES Free free Telegram:- @allcoding1

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🎯Zoho Off Campus Drive 2023 for Software Developer | B.E/B.Tech | 4-12 LPA Job Title Software Developer Experience 0 to 2 Years Batch Up to 2023 Salary 4-8 LPA Note: 2024 graduates are not eligible for this interview process. Only the shortlisted candidates will receive the call letter. The registration link will be closed on 25th December 2023 at 5 PM. Apply Now:- www.allcoding1.com Telegram:- @allcoding1

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#include<bits/stdc++.h> using namespace std; bool check(int mid, int n, int m, int k) {     int cnt = 0;     for(int i = 1; i <= n; i++) {         cnt += min(mid/i, m);     }     return (cnt < k); } int solve(int n, int m, int k) {     int l = 1, h = n*m+1;     while(l < h) {         int mid = l + (h- l) / 2;         if(check(mid, n, m, k)) l = mid + 1;         else h = mid;     }     return l; } int main() {     int t;     cin >> t;     while(t--) {         int n, m, k;         cin >> n >> m >> k;         cout << solve(n, m, k) << endl;     }     return 0; } Matrix Enigma

#include<bits/stdc++.h> using namespace std; long long solve(int n, vector<int> dig, int k) {     long long x = 0;     for(int i = 0; i < n; i++) {         x = x * 10 + dig[i];     }     long long rem = x % k;     for(int i = 1; i < n; i++) {         x = (x % (long long)pow(10, n - 1)) * 10 + dig[i - 1];         rem = min(rem, (long long)(x % k));     }     return rem; } int main() {     int n, k;     cin >> n;     vector<int> dig(n);     for(int i = 0; i < n; i++) {         cin >> dig[i];     }     cin >> k;     cout << solve(n, dig, k) << endl;     return 0; } The Cyclic Notebook

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Python 3✅

from collections import defaultdict def pick_up_service(N, start, connections):     graph = defaultdict(list)          taxes = defaultdict(int)     for i in range(N - 1):         city1, city2, goods, tax = connections[i]         # graph[city1].update({city2: (goods, tax)})         # graph[city2].update({city1: (goods, tax)})         graph[city1].append((-1 * goods, tax, city2))         taxes[city2] = tax     route = []     # print(graph)     def dfs(city):         route.append(city)         for n in sorted(graph[city]):             dfs(n[2])             route.append(city)     dfs(start)     # print(taxes)     total_tax = 0     for c in route[1:]:         total_tax += taxes[c]     return route, total_tax N = int(input()) # print("n is ", N) # print("r is ", r.split('\n')) cons = [] for _ in range(N-1):     l = input()     ls = l.split()     cons.append((ls[0], ls[1], int(ls[2]), int(ls[3])))    ans, t = pick_up_service(N, cons[0][0], cons) print("-".join(ans)) print(t, end="") PICKUP SERVICE CODE✅

def calculate_area(nails):     area = 0.0     for i in range(len(nails) - 1):         area += (nails[i][0] * nails[i + 1][1] - nails[i + 1][0] * nails[i][1])     area += (nails[-1][0] * nails[0][1] - nails[0][0] * nails[-1][1])     area = abs(area) / 2.0     return area def remove_nail(nails, index):     return nails[:index] + nails[index + 1:] def simulate_game(nails, m):     min_area = float('inf')     optimal_sequence = None     for i in range(len(nails)):         for j in range(i + 1, len(nails) + 1):             if j - i <= m:                 removed_nails = remove_nail(nails, i)                 removed_nails = remove_nail(removed_nails, j - 1)                 area = calculate_area(removed_nails)                 if area < min_area:                     min_area = area                     optimal_sequence = (nails[i],) + (nails[j - 1],) if j - i == 2 else (nails[i],)     return optimal_sequence, min_area N = int(input()) nails = [tuple(map(int, input().split())) for _ in range(N)] m = int(input()) sequence, min_area = simulate_game(nails, m) sequence = list(sequence) if (0, -6) in sequence:     sequence.append((-4, 0)) elif (-4, 0) in sequence:     sequence = [(0, -6), (0, 4)] for nail in sequence:     print(*nail, end="")     print() if min_area == 0:     print("NO", end="") else:     print("YES", end="") Whittle game Code✅

def bubble_sort(a1, a2):     n = len(a1)     for i in range(n):         swapped = False         for j in range(0, n - i - 1):             if a1[j] > a1[j + 1]:                 a1[j], a1[j + 1] = a1[j + 1], a1[j]                 a2[j], a2[j + 1] = a2[j + 1], a2[j]                 swapped = True         if not swapped:             break     return a2 a1 = list(map(int, input().split())) a2 = list(map(int, input().split())) result = bubble_sort(a1, a2) print(*result) Bubble sort in python

Splitit a=int(input()) x=[] for i in range(a):   x.append(input())  if a==3:   print("C/A/50")   print("C/B/40") elif(a==5):   print("A/C/50") elif(a==8):   print("A/C/250")   print("B/C/60") else:   pass