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int solve(int n, vector<int>& arr) {     while (arr.size() > 1) {         int len = INT_MAX;         int idx = -1;         for (int i = 0; i < arr.size() - 1; ++i) {             int d = arr[i + 1];             if (d == 0 || arr[i] == 0) {                 continue;             }             int r = min(arr[i] % d, d % arr[i]);             if (r < len) {                 len = r;                 idx = i;             }         }         if (idx == -1) {             break;         }         int d = arr[idx + 1];         if (d != 0) {             arr[idx] = min(arr[idx] % d, d % arr[idx]);         }         arr.erase(arr.begin() + idx + 1);     }     return arr.size(); } Women Day Mathematics Challenge Telegram:- @allcoding1

#include <iostream> #include <sql.h> #include <sqlext.h> #define MAX_QUERY_LEN 1000 int main() { // Declare variables for ODBC connection SQLHENV henv; SQLHDBC hdbc; SQLHSTMT hstmt; SQLRETURN retcode; // Allocate environment handle retcode = SQLAllocHandle(SQL_HANDLE_ENV, SQL_NULL_HANDLE, &amp;henv); // Set the ODBC version to use retcode = SQLSetEnvAttr(henv, SQL_ATTR_ODBC_VERSION, (SQLPOINTER)SQL_OV_ODBC3, 0); // Allocate connection handle retcode = SQLAllocHandle(SQL_HANDLE_DBC, henv, &amp;hdbc); // Connect to the data source retcode = SQLConnect(hdbc, (SQLCHAR*)"your_datasource", SQL_NTS, (SQLCHAR*)"username", SQL_NTS, (SQLCHAR*)"password", SQL_NTS); // Allocate statement handle retcode = SQLAllocHandle(SQL_HANDLE_STMT, hdbc, &amp;hstmt); // Prepare the SQL query char query[MAX_QUERY_LEN] = "SELECT DATE_FORMAT(date_column, '%Y-%m') AS month_year, source, COUNT(*) AS total_number FROM your_table WHERE YEAR(date_column) = '2022' AND (source = 'Jobs' OR source = 'Freelancers') GROUP BY month_year, source ORDER BY month_year ASC, source ASC"; // Execute the SQL query retcode = SQLExecDirect(hstmt, (SQLCHAR*)query, SQL_NTS); // Fetch and process the results while (SQLFetch(hstmt) == SQL_SUCCESS) { // Process the retrieved data here } // Free the handles SQLFreeHandle(SQL_HANDLE_STMT, hstmt); SQLDisconnect(hdbc); SQLFreeHandle(SQL_HANDLE_DBC, hdbc); SQLFreeHandle(SQL_HANDLE_ENV, henv); return 0; } Please note that the above code provides a basic framework for executing SQL queries in C++. You will need to replace your_datasource, username, password, your_table, and date_column with your actual database connection details, table name, and column name. Telegram:- @allcoding1

#include <iostream>
#include <string>
#include <iomanip>
#include <vector>
#include <algorithm>

struct Client {
    std::string name;
    double total_invested_in_bonds;
    double total_invested_in_stocks;
};

bool compareByBonds(const Client &amp;a, const Client &amp;b) {
    return a.total_invested_in_bonds &gt; b.total_invested_in_bonds;
}

int main() {
    std::vector<client> clients = {
        {"Client1", 7500.0, 3000.0},
        {"Client2", 6000.0, 5000.0},
        {"Client3", 4000.0, 6000.0},
        // Add more clients as needed
    };

    // Sort clients based on total_invested_in_bonds in descending order
    std::sort(clients.begin(), clients.end(), compareByBonds);

    // Display the result
    std::cout &lt;&lt; std::left &lt;&lt; std::setw(15) &lt;&lt; "Client Name" 
              &lt;&lt; std::setw(25) &lt;&lt; "Total Invested in Bonds"
              &lt;&lt; "Total Invested in Stocks" &lt;&lt; std::endl;

    for (const auto &amp;client : clients) {
        if (client.total_invested_in_bonds &gt; 5000.00) {
            std::cout &lt;&lt; std::left &lt;&lt; std::setw(15) &lt;&lt; client.name
                      &lt;&lt; std::fixed &lt;&lt; std::setprecision(2)
                      &lt;&lt; std::setw(25) &lt;&lt; client.total_invested_in_bonds
                      &lt;&lt; client.total_invested_in_stocks &lt;&lt; std::endl;
        }
    }

    return 0;
}

You can modify the clients vector to include more clients with their respective investments in bonds and stocks. When you run this program, it will display the result according to the specified requirements.</client></algorithm></vector></iomanip></string></iostream> Telegram:- @allcoding1

Valid permutations Telegram:- @allcoding1

#include <iostream>
#include <vector>
using namespace std;

bool isValidPermutation(const vector<int>&amp; permutation) {
    for (int i = 0; i &lt; permutation.size(); i++) {
        if (permutation[i] % (i + 1) != 0 || (i + 1) % permutation[i] != 0) {
            return false;
        }
    }
    return true;
}

void generatePermutations(vector<int>&amp; nums, int start, vector<vector<int>&gt;&amp; result) {
    if (start == nums.size()) {
        result.push_back(nums);
        return;
    }
    for (int i = start; i &lt; nums.size(); i++) {
        swap(nums[start], nums[i]);
        generatePermutations(nums, start + 1, result);
        swap(nums[start], nums[i]);
    }
}

int countValidPermutations(int N) {
    vector<int> nums(N);
    for (int i = 0; i &lt; N; i++) {
        nums[i] = i + 1;
    }
    vector<vector<int>&gt; permutations;
    generatePermutations(nums, 0, permutations);

    int count = 0;
    for (const auto&amp; perm : permutations) {
        if (isValidPermutation(perm)) {
            count++;
        }
    }
    return count;
}

int main() {
    int N = 2;
    cout &lt;&lt; "Number of valid permutations: " &lt;&lt; countValidPermutations(N) &lt;&lt; endl;
    return 0;
}

Valid permutations Telegram:- @allcoding1

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int min(string str){ unordered_map<char,int>mp; for(char :str){   mp[ch]++; } unodered_set<int>d; for(auto it:mp){   d.insert(it.second); } return d.size(); } Music Teacher Only 4 test cases pass Telegram:- @allcoding1

#include <iostream> #include <cmath> struct Circle {     double x; // x-coordinate of the center     double y; // y-coordinate of the center     double r; // radius }; double distanceBetweenCenters(Circle A, Circle B) {     return sqrt(pow((B.x - A.x), 2) + pow((B.y - A.y), 2)); } int main() {     Circle A, B;     // Example values     A.x = 0;     A.y = 0;     A.r = 5;     B.x = 10;     B.y = 0;     B.r = 7;     double distance = distanceBetweenCenters(A, B);     double sumOfRadii = A.r + B.r;     double differenceOfRadii = abs(A.r - B.r);     if (distance == sumOfRadii) {         std::cout &lt;&lt; "The circles are touching at a single point." &lt;&lt; std::endl;     } else if (distance &lt; sumOfRadii) {         std::cout &lt;&lt; "The circles are intersecting." &lt;&lt; std::endl;     } else if (distance == differenceOfRadii) {         std::cout &lt;&lt; "The circles are touching from within or without." &lt;&lt; std::endl;     } else {         std::cout &lt;&lt; "The circles are not intersecting." &lt;&lt; std::endl;     }     if ((A.x == B.x) &amp;&amp; (A.y == B.y) &amp;&amp; (A.r == B.r)) {         std::cout &lt;&lt; "The circles are concentric." &lt;&lt; std::endl;     }     return 0; } C++ Telegram:- @allcoding1

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Solve the Equation Telegram:- @allcoding1

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#include<bits/stdc++.h> using namespace std; int main(){     int n,m;     cin>>n>>m;     vector<int>ans(n);     if(n<=m){         for(int i=0;i<n;i++){             ans[i]=i+1;         }     }     else{                  int k=n/m;         // int r=n%m;         int j=0;         for(int i=0;i<n;i++){             ans[i]=j+1;             j++;             j%=m;         }                       }     for(int i=0;i<n;i++){         cout<<ans[i]<<" ";     }     cout<<endl; } King Dreams ✅ Intuit Telegram:-- @allcoding1

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`cpp class Solution { public:   int minOperations(vector<int>& nums, int x, int y) {     int l = 0;     int r = ranges::max(nums);     while (l < r) {       const int m = (l + r) / 2;       if (isPossible(nums, x, y, m))         r = m;       else         l = m + 1;     }     return l;   } private:   bool isPossible(const vector<int>& nums, int x, int y, int m) {     long long additionalOps = 0;     for (const int num : nums)       additionalOps += max(0LL, (num - 1LL * y * m + x - y - 1) / (x - y));     return additionalOps <= m;   } }; Job Execution ✅ Telegram:- @allcoding1

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