ar
Feedback
MTHREE exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer

MTHREE exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer

الذهاب إلى القناة على Telegram

🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srksvk

إظهار المزيد

📈 نظرة تحليلية على قناة تيليجرام MTHREE exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer

تُعد قناة MTHREE exam help ! Infosys exam help ! Cognizant exam help ! Amazon exam answer (@coding_are) في القطاع اللغوي الإنكليزية لاعباً نشطاً. يضم المجتمع حالياً 13 242 مشتركاً، محتلاً المرتبة 15 362 في فئة التعليم والمرتبة 32 092 في منطقة الهند.

📊 مؤشرات الجمهور والحراك

منذ تأسيسه في невідомо، حقق المشروع نمواً سريعاً وجمع 13 242 مشتركاً.

بحسب آخر البيانات بتاريخ 18 يونيو, 2026، تحافظ القناة على نشاط مستقر. خلال آخر 30 يوماً تغيّر عدد الأعضاء بمقدار -138، وفي آخر 24 ساعة بمقدار -2، مع بقاء الوصول العام مرتفعاً.

  • حالة التحقق: غير موثّقة
  • معدل التفاعل (ER): يبلغ متوسط تفاعل الجمهور 2.93‎%. وخلال أول 24 ساعة من النشر يحصد المحتوى عادةً 1.11‎% من ردود الفعل نسبةً إلى إجمالي المشتركين.
  • وصول المنشورات: يحصل كل منشور على متوسط 388 مشاهدة. وخلال اليوم الأول يجمع عادةً 147 مشاهدة.
  • التفاعلات والاستجابة: يتفاعل الجمهور بانتظام؛ متوسط التفاعلات لكل منشور يبلغ 2.
  • الاهتمامات الموضوعية: يركز المحتوى على مواضيع رئيسية مثل placement, gaurntee, suree, capgemini, infosy.

📝 الوصف وسياسة المحتوى

يصف المؤلف القناة بأنها مساحة للتعبير عن الآراء الذاتية:
🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srks...

بفضل وتيرة التحديث المرتفعة (أحدث البيانات بتاريخ 19 يونيو, 2026) تحافظ القناة على حداثتها ومستوى وصول مرتفع. وتُظهر التحليلات تفاعلاً نشطاً من الجمهور، ما يجعلها نقطة تأثير مهمة ضمن فئة التعليم.

13 242
المشتركون
-224 ساعات
-457 أيام
-13830 أيام
أرشيف المشاركات
I will upload today only fully passed code so don't worry Just share my group ✅ https://t.me/codeing_are

Run in java File name should be same as class name

import java.util.*; public class DesertPathfinder { static class Cell implements Comparable<Cell> { int row, col, waterCost; Cell(int row, int col, int waterCost) { this.row = row; this.col = col; this.waterCost = waterCost; } @Override public int compareTo(Cell other) { return Integer.compare(this.waterCost, other.waterCost); } } public static int calculateMinWater(char[][] grid, int gridSize) { int[] rowOffsets = {-1, 1, 0, 0}; int[] colOffsets = {0, 0, -1, 1}; int[][] waterUsage = new int[gridSize][gridSize]; boolean[][] isVisited = new boolean[gridSize][gridSize]; for (int[] row : waterUsage) { Arrays.fill(row, Integer.MAX_VALUE); } int startRow = -1, startCol = -1, endRow = -1, endCol = -1; for (int row = 0; row < gridSize; row++) { for (int col = 0; col < gridSize; col++) { if (grid[row][col] == 'S') { startRow = row; startCol = col; } else if (grid[row][col] == 'E') { endRow = row; endCol = col; } } } PriorityQueue<Cell> priorityQueue = new PriorityQueue<>(); priorityQueue.offer(new Cell(startRow, startCol, 0)); waterUsage[startRow][startCol] = 0; while (!priorityQueue.isEmpty()) { Cell current = priorityQueue.poll(); int currentRow = current.row; int currentCol = current.col; if (isVisited[currentRow][currentCol]) { continue; } isVisited[currentRow][currentCol] = true; if (currentRow == endRow && currentCol == endCol) { return waterUsage[currentRow][currentCol]; } for (int i = 0; i < 4; i++) { int nextRow = currentRow + rowOffsets[i]; int nextCol = currentCol + colOffsets[i]; if (nextRow >= 0 && nextCol >= 0 && nextRow < gridSize && nextCol < gridSize && grid[nextRow][nextCol] != 'M' && !isVisited[nextRow][nextCol]) { int newCost = waterUsage[currentRow][currentCol] + (grid[currentRow][currentCol] == 'T' && grid[nextRow][nextCol] == 'T' ? 0 : 1); if (newCost < waterUsage[nextRow][nextCol]) { waterUsage[nextRow][nextCol] = newCost; priorityQueue.offer(new Cell(nextRow, nextCol, newCost)); } } } } return -1; } public static void main(String[] args) { Scanner scanner = new Scanner(System.in); int gridSize = scanner.nextInt(); scanner.nextLine(); char[][] grid = new char[gridSize][gridSize]; for (int row = 0; row < gridSize; row++) { String[] elements = scanner.nextLine().split(" "); for (int col = 0; col < gridSize; col++) { grid[row][col] = elements[col].charAt(0); } } int result = calculateMinWater(grid, gridSize); System.out.print(result); scanner.close(); } } Desert queen 👑👑 https://t.me/codeing_are

Hii guys 👍 How many students started exam now Giver hert to this post

NEED more TCS CODEVITA ANSWERS ? Give heart to this post ❤️ Fully passed code 👍

Next code loded 👇⬇️⬇️⬇️⬇️ https://t.me/codeing_are Join the group

#include <iostream> #include <vector> #include <set> #include <cmath> #include <map> #include <algorithm> using namespace std; polygon using the Shoelace Theorem int calculateArea(const vector<pair<int, int>>& polygon) { int n = polygon.size(); int area = 0; for (int i = 0; i < n; i++) { int j = (i + 1) % n; area += polygon[i].first * polygon[j].second; area -= polygon[j].first * polygon[i].second; } return abs(area) / 2; } are connected bool areConnected(pair<int, int> a, pair<int, int> b, pair<int, int>& p1, pair<int, int>& p2) { return (p1 == a && p2 == b) || (p1 == b && p2 == a); } int main() { int N; cin >> N; vector<pair<int, int>> coordinates; vector<vector<pair<int, int>>> segments(N); set<pair<int, int>> points; store them as pairs for (int i = 0; i < N; i++) { int x1, y1, x2, y2; cin >> x1 >> y1 >> x2 >> y2; coordinates.push_back({x1, y1}); coordinates.push_back({x2, y2}); points.insert({x1, y1}); points.insert({x2, y2}); } vector<pair<int, int>> polygon; int maxArea = 0; to form polygons for (auto p1 = points.begin(); p1 != points.end(); ++p1) { for (auto p2 = next(p1); p2 != points.end(); ++p2) { polygon.push_back(*p1); polygon.push_back(*p2); maxArea = max(maxArea, calculateArea(polygon)); } } cout << maxArea << endl; return 0; } maximum area

#include <iostream> #include <unordered_map> #include <unordered_set> #include <queue> #include <sstream> #include <vector> using namespace std; unordered_map<string, int> calculateLevels(unordered_map<string, vector<string>>& graph, const string& root) { unordered_map<string, int> levels; queue<pair<string, int>> q; q.push(make_pair(root, 1)); while (!q.empty()) { pair<string, int> current = q.front(); q.pop(); string node = current.first; int level = current.second; levels[node] = level; for (const string& child : graph[node]) { q.push(make_pair(child, level + 1)); } } return levels; } int main() { int n; cin >> n; unordered_map<string, vector<string>> graph; unordered_set<string> children; unordered_set<string> nodes; for (int i = 0; i < n; ++i) { string parent, child; cin >> parent >> child; graph[parent].push_back(child); children.insert(child); nodes.insert(parent); nodes.insert(child); } string root; for (const string& node : nodes) { if (children.find(node) == children.end()) { root = node; break; } } unordered_map<string, int> levels = calculateLevels(graph, root); cin.ignore(); string inputLine, word; getline(cin, inputLine); stringstream ss(inputLine); int totalValue = 0; while (ss >> word) { if (levels.find(word) != levels.end()) { totalValue += levels[word]; } else { totalValue += -1; } } cout << totalValue << endl; return 0; } String Puzzle Done ✅

How many writing now exam Hit ♥️?

Ready for next everyone ✅

from collections import deque def count_infected_neighbors(board, x, y): size = len(board) infected_count = 0 for dx in [-1, 0, 1]: for dy in [-1, 0, 1]: if dx == 0 and dy == 0: continue nx, ny = x + dx, y + dy if 0 <= nx < size and 0 <= ny < size and board[nx][ny] == 1: infected_count += 1 return infected_count def plague_simulation(board): size = len(board) new_board = [row[:] for row in board] for x in range(size): for y in range(size): infected_count = count_infected_neighbors(board, x, y) if board[x][y] == 0 and infected_count == 3: new_board[x][y] = 1 elif board[x][y] == 1 and (infected_count < 2 or infected_count > 3): new_board[x][y] = 0 return new_board def find_path(grid_size, initial_board): board = [[1 if cell == '1' else 0 for cell in row] for row in initial_board] start_x, start_y, end_x, end_y = -1, -1, -1, -1 for x in range(grid_size): for y in range(grid_size): if initial_board[x][y] == 's': start_x, start_y = x, y board[x][y] = 0 if initial_board[x][y] == 'd': end_x, end_y = x, y board[x][y] = 0 queue = deque([(start_x, start_y, board, 0)]) visited_states = set() while queue: x, y, current_board, days = queue.popleft() if x == end_x and y == end_y: return days state = (x, y, tuple(map(tuple, current_board))) if state in visited_states: continue visited_states.add(state) next_board = plague_simulation(current_board) for dx, dy in [(0, 0), (-1, 0), (1, 0), (0, -1), (0, 1)]: nx, ny = x + dx, y + dy if 0 <= nx < grid_size and 0 <= ny < grid_size and next_board[nx][ny] == 0: queue.append((nx, ny, next_board, days + 1)) return -1 if name == "main": n = int(input()) grid = [input().strip() for _ in range(n)] print(find_path(n, grid) + 1) Plague 2050 ✅✅ Full passed✅✅

Full accepted Please shared my group everyone ✅✅ https://t.me/codeing_are

def rotate_layer(layer, positions, direction, odd_layer): n = len(layer) rotated = [None] * n if direction == "clockwise": for i in range(n): rotated[(i + positions) % n] = layer[i] else: # counterclockwise for i in range(n): rotated[(i - positions) % n] = layer[i] for i in range(n): if odd_layer: rotated[i] = chr(((ord(rotated[i]) - ord('A') - 1) % 26) + ord('A')) else: rotated[i] = chr(((ord(rotated[i]) - ord('A') + 1) % 26) + ord('A')) return rotated def apply_query(matrix, row, col, size): layers = [] for layer in range(size // 2): current_layer = [] for j in range(col + layer, col + size - layer): current_layer.append(matrix[row + layer][j]) for i in range(row + layer + 1, row + size - layer - 1): current_layer.append(matrix[i][col + size - layer - 1]) for j in range(col + size - layer - 1, col + layer - 1, -1): current_layer.append(matrix[row + size - layer - 1][j]) for i in range(row + size - layer - 2, row + layer, -1): current_layer.append(matrix[i][col + layer]) layers.append(current_layer) for layer_idx, layer in enumerate(layers): odd_layer = (layer_idx + 1) % 2 == 1 direction = "counterclockwise" if odd_layer else "clockwise" positions = layer_idx + 1 rotated_layer = rotate_layer(layer, positions, direction, odd_layer) idx = 0 for j in range(col + layer_idx, col + size - layer_idx): matrix[row + layer_idx][j] = rotated_layer[idx] idx += 1 for i in range(row + layer_idx + 1, row + size - layer_idx - 1): matrix[i][col + size - layer_idx - 1] = rotated_layer[idx] idx += 1 for j in range(col + size - layer_idx - 1, col + layer_idx - 1, -1): matrix[row + size - layer_idx - 1][j] = rotated_layer[idx] idx += 1 for i in range(row + size - layer_idx - 2, row + layer_idx, -1): matrix[i][col + layer_idx] = rotated_layer[idx] idx += 1 def process_matrix(n, matrix, queries): for row, col, size in queries: apply_query(matrix, row, col, size) result = ''.join(''.join(row) for row in matrix) return result n = int(input()) matrix = [list(input().strip().split()) for _ in range(n)] q = int(input().strip()) queries = [tuple(map(int, input().strip().split())) for _ in range(q)] result = process_matrix(n, matrix, queries) print(result, end="") Matrix rotation

Ready for next answer 👇👇👇👇👇

How many writeing exam now Hit ♥️

def min_cost_to_form_string(substrings, main_string): inf = float('inf') dp = [inf] * (len(main_string) + 1) dp[0] = 0 # Cost to form an empty string is 0 substrings with their costs substring_cost = {} for substring, cost in substrings: substring_cost[substring] = cost for i in range(1, len(main_string) + 1): for j in range(i): sub = main_string[j:i] # Get the substring from j to i if sub in substring_cost:ue dp[i] = min(dp[i], dp[j] + substring_cost[sub]) dp[len(main_string)] if dp[len(main_string)] == inf: return "Impossible" else: return dp[len(main_string)] if name == "main": N = int(input()) substrings = [] for _ in range(N): line = input().split() substrings.append((line[0], int(line[1]))) # Append tuple (substring, cost) main_string = input().strip() result = min_cost_to_form_string(substrings, main_string) print(result) Form the string