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ACCENTURE EXAM HELP ! CISCO EXAM !

ACCENTURE EXAM HELP ! CISCO EXAM !

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🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srksvk

إظهار المزيد

📈 نظرة تحليلية على قناة تيليجرام ACCENTURE EXAM HELP ! CISCO EXAM !

تُعد قناة ACCENTURE EXAM HELP ! CISCO EXAM ! (@coding_are) في القطاع اللغوي الإنكليزية لاعباً نشطاً. يضم المجتمع حالياً 13 208 مشتركاً، محتلاً المرتبة 15 294 في فئة التعليم والمرتبة 31 490 في منطقة الهند.

📊 مؤشرات الجمهور والحراك

منذ تأسيسه في невідомо، حقق المشروع نمواً سريعاً وجمع 13 208 مشتركاً.

بحسب آخر البيانات بتاريخ 30 يونيو, 2026، تحافظ القناة على نشاط مستقر. خلال آخر 30 يوماً تغيّر عدد الأعضاء بمقدار -144، وفي آخر 24 ساعة بمقدار 6، مع بقاء الوصول العام مرتفعاً.

  • حالة التحقق: غير موثّقة
  • معدل التفاعل (ER): يبلغ متوسط تفاعل الجمهور 3.08‎%. وخلال أول 24 ساعة من النشر يحصد المحتوى عادةً 1.29‎% من ردود الفعل نسبةً إلى إجمالي المشتركين.
  • وصول المنشورات: يحصل كل منشور على متوسط 407 مشاهدة. وخلال اليوم الأول يجمع عادةً 170 مشاهدة.
  • التفاعلات والاستجابة: يتفاعل الجمهور بانتظام؛ متوسط التفاعلات لكل منشور يبلغ 2.
  • الاهتمامات الموضوعية: يركز المحتوى على مواضيع رئيسية مثل placement, gaurntee, suree, capgemini, infosy.

📝 الوصف وسياسة المحتوى

يصف المؤلف القناة بأنها مساحة للتعبير عن الآراء الذاتية:
🔥Guys plz Stop fearing for daily exams 📝 👨‍💻 @srksvk is here to help you all at lowest cost possible.💪 🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company 🔥Effort from our side = 💯 📱Main Channel: @coding_are 📱Tel I'd : @srks...

بفضل وتيرة التحديث المرتفعة (أحدث البيانات بتاريخ 01 يوليو, 2026) تحافظ القناة على حداثتها ومستوى وصول مرتفع. وتُظهر التحليلات تفاعلاً نشطاً من الجمهور، ما يجعلها نقطة تأثير مهمة ضمن فئة التعليم.

13 208
المشتركون
+624 ساعات
-127 أيام
-14430 أيام
أرشيف المشاركات
def max_efficiency(numbers): numbers.sort() n = len(numbers) max_efficiency = 0 for i in range(n): efficiency = 0 for j in range(i, n): efficiency += numbers[j] * (j - i + 1) max_efficiency = max(max_efficiency, efficiency) return max_efficiency # Input parsing numbers = list(map(int, input().split())) # Output result = max_efficiency(numbers) print(result if result >= 0 else 0) Sport's daye full running 💯💯💯💯 In python 3 Now share ✅✅

import math mapval = { "add": -1, "sub": -2, "mul": -3, "rem": -4, "pow": -5, "zero": 0, "one": 1, "two": 2, "three": 3, "four": 4, "five": 5, "six": 6, "seven": 7, "eight": 8, "nine": 9 } def values(): global mapval mapval = { "add": -1, "sub": -2, "mul": -3, "rem": -4, "pow": -5, "zero": 0, "one": 1, "two": 2, "three": 3, "four": 4, "five": 5, "six": 6, "seven": 7, "eight": 8, "nine": 9 } def generate_value(s, stack): s += 'c' str_val = "" sn = "" for char in s: if char == 'c': if str_val not in mapval: return False sn += str(mapval[str_val]) str_val = "" else: str_val += char ans = int(sn) stack.append(ans) return True def solve_this(stack1, stack2): while stack1: top = stack1.pop() if top < 0 and len(stack2) < 2: return "expression is not complete or invalid" elif top < 0: val1 = stack2.pop() val2 = stack2.pop() if top == -1: new_val = val1 + val2 elif top == -4: new_val = val1 % val2 elif top == -2: new_val = val1 - val2 elif top == -3: new_val = val1 * val2 elif top == -5: new_val = int(math.pow(val1, val2)) stack2.append(new_val) else: stack2.append(top) return str(stack2[0]) if len(stack2) == 1 else "expression is not complete or invalid" def perform_task(s, stack): i = 0 str_val = "" s += " " count_of_c = 0 while i < len(s): if s[i] == ' ': if str_val not in mapval: if count_of_c == 0: return "expression evaluation stopped invalid words present" if not generate_value(str_val, stack): return "expression evaluation stopped invalid words present" count_of_c = 0 else: stack.append(mapval[str_val]) str_val = "" else: if s[i] == 'c': count_of_c += 1 str_val += s[i] i += 1 return "" def solve_it(s): st = [] st1 = [] an = perform_task(s, st) if an != "": return an return solve_this(st, st1) def main(): values() s = input() print(solve_it(s)) if name == "main": main() No more symobol python Fully passed ✅💯👍🎉

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#include<bits/stdc++.h> using namespace std; int main() {     int x,y,x1,y1,x2,y2;     cin>>x>>y>>x1>>y1>>x2>>y2;     x=abs(x);     y=abs(y);     x1=abs(x1);     y1=abs(y1);     x2=abs(x2);     y2=abs(y2);     int r1 = ceil(sqrt(((x1-x)*(x1-x))+((y1-y)*(y1-y))));     int r2 = ceil(sqrt(((x2-x)*(x2-x))+((y2-y)*(y2-y))));     int a1 = ceil(3.14*r1*r1);     int a2 = ceil(3.14*r2*r2);     if(a2>a1)     {         int e = a2-a1;         int f = ceil(sqrt(e));         int g = f*f;         int h = g-e;         int i = h*20;         cout<<"Krishna ";         cout<<i;     }     else if(a1>a2)     {       int p = a1-a2;       int q = p*20;       cout<<"Shiva ";       cout<<q;     }     else if(a1==a2)     {         cout<<"-1";     } } FencingProblem:  Shiva and Krishna public test cases passed C++ TCS CODEVITA SOLUTIONS @codeing_area @codeing_area

#include<bits/stdc++.h> using namespace std; int main() {     int x,y,x1,y1,x2,y2;     cin>>x>>y>>x1>>y1>>x2>>y2;     x=abs(x);     y=abs(y);     x1=abs(x1);     y1=abs(y1);     x2=abs(x2);     y2=abs(y2);     int r1 = ceil(sqrt(((x1-x)*(x1-x))+((y1-y)*(y1-y))));     int r2 = ceil(sqrt(((x2-x)*(x2-x))+((y2-y)*(y2-y))));     int a1 = ceil(3.14*r1*r1);     int a2 = ceil(3.14*r2*r2);     if(a2>a1)     {         int e = a2-a1;         int f = ceil(sqrt(e));         int g = f*f;         int h = g-e;         int i = h*20;         cout<<"Krishna ";         cout<<i;     }     else if(a1>a2)     {       int p = a1-a2;       int q = p*20;       cout<<"Shiva ";       cout<<q;     }     else if(a1==a2)     {         cout<<"-1";     } } FencingProblem:  Shiva and Krishna public test cases passed C++ TCS CODEVITA SOLUTIONS @codeing_area @codeing_area

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def max_efficiency(numbers): numbers.sort() n = len(numbers) max_efficiency = 0 for i in range(n): efficiency = 0 for j in range(i, n): efficiency += numbers[j] * (j - i + 1) max_efficiency = max(max_efficiency, efficiency) return max_efficiency # Input parsing numbers = list(map(int, input().split())) # Output result = max_efficiency(numbers) print(result if result >= 0 else 0) Sport's daye full running 💯💯💯💯 In python Now share ✅✅ Make it 5k

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def max_points(chocolates,initial):   chocolates=sorted(chocolates)   points=1   l=[1]   i=0   while i < len(chocolates):     if chocolates[i]<=initial:       initial=initial-chocolates[i]       points+=1       i+=1     else:       points-=1       initial+=chocolates[-1]       chocolates.pop()     l.append(points)   return max(l) # Example usage: chocolates_list = list(map(int, input().split()))  # Input list of chocolates initial_chocolates = int(input())  # Initial chocolates Bittu has result = max_points(chocolates_list, initial_chocolates) print(result,end="") Choclate Code TCS CODEVITA PYTHON3 Share fasttt @codeing_area

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#include <iostream> #include <vector> #include <algorithm> using namespace std; int max_efficiency(vector<int>& numbers) { sort(numbers.begin(), numbers.end()); int n = numbers.size(); int max_efficiency = 0; for (int i = 0; i < n; ++i) { int efficiency = 0; for (int j = i; j < n; ++j) { efficiency += numbers[j] * (j - i + 1); } max_efficiency = max(max_efficiency, efficiency); } return max_efficiency; } int main() { // Input parsing int n; cin >> n; vector<int> numbers(n); for (int i = 0; i < n; ++i) { cin >> numbers[i]; } // Output int result = max_efficiency(numbers); cout << (result >= 0 ? result : 0) << endl; return 0; } . sports codee in C+++ Fully passsd ✅✅✅✅✅ Now make it 5k

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def toggle(num):     result = ""     for bit in num:         if bit == "0":             result += "1"         else:             result += "0"     return result def get_max_sum(arr, k):     max_val = max(arr)     max_index = arr.index(max_val)     left = max(0, max_index-k)     right = min(len(arr)-1, max_index+k)          selected = arr[left:max_index+1] + arr[max_index:right+1]      arr = [x for x in arr if x not in selected]          return sum(selected), arr # Input  arr = list(map(int, input().split()))   a1, b1 = input().split() a2, b2 = input().split() k = int(input()) sum1, sum2 = 0, 0 while arr:     s1, arr = get_max_sum(arr, k)      sum1 += s1          if not arr:         break              s2, arr = get_max_sum(arr, k)     sum2 += s2      if sum1 > sum2:     a1 = toggle(a1)     b2 = toggle(b2) else:     a2 = toggle(a2)      b1 = toggle(b1) xor1 = int(a1, 2) ^ int(b1, 2)   xor2 = int(a2, 2) ^ int(b2, 2) if xor1 > xor2:     print("Rahul",end="") elif xor2 > xor1:     print("Rupesh",end="") else:     print("both",end="") WHO IS LUCKY CODE TCS CODEVITA PYTHON3