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LeetCode, GeeksForGeeks Problem of the day solution

LeetCode, GeeksForGeeks Problem of the day solution

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Complete daily challenges from LeetCode, GeeksForGeeks and redeem their rewards Channel link : https://t.me/leetcode_gfg_potd

إظهار المزيد
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المشتركون
+224 ساعات
+147 أيام
+2930 أيام
أرشيف المشاركات
GFG | Problem of the day :

class Solution { public: int integerBreak(int n) { if(n==2 || n==3) return n-1; int res =1; while(n>4){ n-=3; res*=3; } return res * n; } };

LeetCode | Daily challenge :

class Solution { public: void rearrange(struct Node *odd) { Node*i = odd; Node*j = odd->next; if(!j || j->next==NULL){return;} Node*prevJ = NULL; while(i!=NULL and j!=NULL){ i->next = j->next; i = j->next; j->next = prevJ; prevJ = j; if(i!=NULL){ if(i->next){j=i->next;} else{i->next = j;break;} } else{ break; } if(j->next==NULL){ j->next = prevJ; break; } } } };

GFG | Problem of the day :

class Solution { public: vector majorityElement(vector& nums) { sort(nums.begin(), nums.end()); int n = nums.size(); if(n==1){ return nums; } else if(n==2 && nums[0] != nums[1]){ return nums; } vector ans; int cnt = 0; int temp = n/3; for(int i=0;i0 && nums[i] == nums[i-1]){ cnt++; if(cnt > temp && find(ans.begin(), ans.end(), nums[i]) == ans.end()){ ans.push_back(nums[i]); } } else{ cnt = 1; } } return ans; } };

LeetCode | Daily challenge :

class Solution { public: long long int solve(string s, int k) { int n = s.size(); long long int c = 0; int j = 0, sz = 0; vectormp(26, 0); for(int i=0; i k) { mp[s[j]-'a']--; if(!mp[s[j]-'a']) sz--; j++; } if(j <= i) c += (i-j+1); } return c; } long long int substrCount (string s, int k) { //code here. return solve(s, k) - solve(s, k-1); } };

GFG | Problem of the day :

class MyHashMap { public: unordered_map mp; MyHashMap() { mp.clear(); } void put(int key, int value) { mp[key] = value; } int get(int key) { if(mp.find(key) != mp.end()){ return mp[key]; } return -1; } void remove(int key) { mp.erase(key); } };

LeetCode | Daily challenge :

class Solution { public: int romanToDecimal(string &str) { unordered_mapmp; mp['I']=1; mp['V']=5; mp['X']=10; mp['L']=50; mp['C']=100; mp['D']=500; mp['M']=1000; int sum=0; int pre=0; for(int i=str.length()-1;i>=0;i--) { if(mp[str[i]] < pre) sum-=mp[str[i]]; else sum+=mp[str[i]]; pre=mp[str[i]]; } return sum; } };

GFG | Problem of the day :

class Solution { public: int numIdenticalPairs(vector& nums) { int ans = 0; unordered_map f; for (int& x : nums) ans += f[x]++; return ans; } };

LeetCode | Daily challenge :

class Solution{ public: string colName (long long int n) { string s=""; while(n!=0){ n=n-1; long long int first=n/26; long long int second=(n+1)-(26*first); s +='A'+second-1; n=first; } reverse(s.begin() , s.end()); return s; } };

GFG | Problem of the day :

class Solution { public: bool winnerOfGame(string colors) { int n = colors.size(); int a = 0,b = 0; for(int i=0;ib)return true; return false; } };

LeetCode | Daily challenge :

class Solution{ public: int distinctSubsequences(string s) { int n=s.size(); long long mod=1e9+7; long long arr[26]={0},pre=1,cur=1; for(int i=0;i