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LeetCode, GeeksForGeeks Problem of the day solution

LeetCode, GeeksForGeeks Problem of the day solution

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Complete daily challenges from LeetCode, GeeksForGeeks and redeem their rewards Channel link : https://t.me/leetcode_gfg_potd

إظهار المزيد
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+224 ساعات
+147 أيام
+2930 أيام
أرشيف المشاركات
GFG | Problem of the day :

class Solution { public: vector> transpose(vector>& matrix) { vector> res(matrix[0].size(), vector(matrix.size())); for(int i=0;i

LeetCode | Daily challenge :

class Solution{ public: //Complete this function //Function to check whether there is a subarray present with 0-sum or not. bool subArrayExists(int arr[], int n) { unordered_map mpp; int sum =0; mpp[0] =true; for(int i =0;i< n;i++){ sum+=arr[i]; if(mpp[sum]) return true; mpp[sum] = true; } return false; } };

GFG | Problem of the day :

class Solution { public: vector inorderTraversal(TreeNode* root) { vector ans; if(root==NULL){ return ans; } TreeNode* curr = root; while(curr!=NULL){ if(curr->left==NULL){ ans.push_back(curr->val); curr = curr->right; } else{ TreeNode* prev = curr->left; while(prev->right != NULL && prev->right != curr){ prev = prev->right; } if(prev->right==NULL){ prev->right = curr; curr= curr->left; } else{ prev->right = NULL; ans.push_back(curr->val); curr=curr->right; } } } return ans; } };

LeetCode | Daily challenge :

class Solution { public: int smithNum(int n) { int sum = 0; int num =n; vector primes; for(int i =2;i< n;i++){ while(num%i == 0){ primes.push_back(i); num/=i; } } num =0; while(n){ int digit = n%10; num+=digit; n/=10; } for(int i =0;i< primes.size();i++){ while(primes[i]){ int digit =primes[i]%10; sum+=digit; primes[i]/=10; } } return num == sum; } };

GFG | Problem of the day :

class Solution { public: string tree2str(TreeNode* root) { if(root==nullptr){ return ""; } string s = to_string(root->val); if(root->left){ s+= '(' + tree2str(root->left) + ')'; } if(root->right){ if(root->left==nullptr){ s += "()"; } s+= '(' + tree2str(root->right) + ')'; } return s; } };

LeetCode | Daily challenge :

#define ll long long class Solution { public: bool isPrime(int n) { for(int i=2;i*i<=n;i++) { if(n%i==0) return 0; } return 1; } int minNumber(int arr[],int N) { ll sum=0; for(int i=0;i<N;i++) sum+=arr[i]; ll temp=sum; while(1) { if(isPrime(temp)) return temp-sum; else temp++; } return 0; } };

GFG | Problem of the day :

class Solution { public: string largestOddNumber(string num) { int n=num.size(); for(int i=n-1;i>=0;i--){ if(num[i]%2==1){ return num.substr(0, i+1); } } return ""; } };

LeetCode | Daily challenge :

class Solution{ public: long countSubarrays(int a[], int n, int L, int R){ vector<int> left(n,-1); vector<int> right(n,n); stack<int> s; for(int i=0;i<n;i++){ while(!s.empty() && a[s.top()]<=a[i]){ s.pop(); } if(!s.empty()){ left[i]=s.top(); } s.push(i); } s=stack<int>(); for(int i=n-1;i>=0;i--){ while(!s.empty() && a[s.top()]<a[i]){ s.pop(); } if(!s.empty()){ right[i]=s.top(); } s.push(i); } long res=0; for(int i=0;i<n;i++){ if(a[i]>=L && a[i]<=R){ int ways=(i-left[i])*(right[i]-i); res+=ways; } } return res; } };

GFG | Problem of the day :

class Solution { public: int totalMoney(int n) { int s = 1, ans = 0; while (n > 0) { for (int i = 0; i < 7 && n-- > 0; ++i) ans += s + i; s++; } return ans; } };

LeetCode | Daily challenge :

class Solution { public: int countX(int L, int R, int X) { int rem; int ans=0; int i=L+1; int times =0; while(i>0 && i