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frequency count -python

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str1 = input() str2 = input () vowels = 'aeiou' c1 = c2 = 0 for ch in str1:   if ch in vowels:     c1 += 1 for ch in str2:   if ch in vowels:     c2 += 1 print(min(c1,c2)) input2[-1] +=1 ans = input2[::-1] i=0 while i<= input1:     if ans[i]>=9:         ans[i+1]+=1         i+=1     else:         print(input1-i)         break Python LCS With Vowels

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(Python3) Total Number of possible pairs(a,b) All test cases passes Telegram:- @Coding_000

def getLargestString(s, k):     frequency_array = [0] * 26     for i in range(len(s)):         frequency_array[ord(s[i]) -                         ord('a')] += 1     ans = ""     i = 25     while i >= 0:         if (frequency_array[i] > k):             temp = k             st = chr( i + ord('a'))                          while (temp > 0):                 ans += st                 temp -= 1                        frequency_array[i] -= k             j = i - 1                          while (frequency_array[j] <= 0 and                    j >= 0):                 j -= 1             if (frequency_array[j] > 0 and                 j >= 0):                 str1 = chr(j + ord( 'a'))                 ans += str1                 frequency_array[j] -= 1                          else:                 break         elif (frequency_array[i] > 0):             temp = frequency_array[i]             frequency_array[i] -= temp             st = chr(i + ord('a'))             while (temp > 0):                 ans += st                 temp -= 1         else:             i -= 1                  return ans           if name == "main":        S = input()     k = 3     print (getLargestString(S, k)) Python Bob code

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