Coding | EXAMS | IBM ACCENTURE | VIRTUSA | IBM | AMAZON | TCS | EPAM | WILEY EDGE | TECH MAHINDRA | JPMORGAN | HCL | WIPRO

Atos Syntel hiring 2023 Batch Apply link given 👇👇 https://tests.mettl.com/drive/Syntellect-2023-BE-MCA-Candidate-Registration-Form/ Apply soon 🔜

Any one want projects -mini or Major 😊 Domain AI/ML contact -@ILOVEU_000 Note -paid 🤑 share✅ share ✅@Coding_000

partition code ✅-python

C++ Retrieve passcode code

retrive pass code ✅✅

😍

strips.sort() fis="" las="" n=len(strips) for i in range(n):     s=strips[i]     fis+=s[1]     las+=s[2] print(fis) print(las) python ✅

retrievepasscode python✅✅

partition creation code-python3

Send all ur questions here https://t.me/exams_discussion https://t.me/exams_discussion share our channel @Coding_000✅✅✅✅✅✅✅

share our channel i will upload fast solutions...✅

Start login guys for 6 pm IBM EXAM

if any one want personal help contact -@ILOVEU_000 Note-paid ✅

Guys,Be ready 6pm slot for Ibm exam codes😊✅ Definitely we will send maximum codes✅❤️ Share this group to ur friends share ✅ share ✅ Keep supporting us ❤️@Coding_000          ➖ @ILOVEU_000 ➖

C++ String Rotation Code

C++ Closure sum Code

closuresum python✅

closure sum code -java

String Rotation import string upper=[] lower=[] for i in string.ascii_uppercase:     upper.append(i) for i in string.ascii_lowercase:     lower.append(i) string="" sentence=input() rotation=int(input()) for i in sentence:     if('a'<=i<='z'):         lek=lower.index(i)         lek=lek+rotation         if(lek>=26):             lek=lek-26             string=string+lower[lek]         else:             string=string+lower[lek]     elif('A'<=i<='z'):         lek=upper.index(i)         lek=lek+rotation         if(lek>26):             lek=lek-26             string=string+upper[lek]         else:             string=string+upper[lek] print(string) python✅

string rotation code ✅