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GeeksForGeeks - POTD | GFG POTD Answer

GeeksForGeeks - POTD | GFG POTD Answer

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إظهار المزيد
1 218
المشتركون
لا توجد بيانات24 ساعات
-97 أيام
-5730 أيام
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18th June : C++ Solution ☝🏼

class Solution { public: int distributeTicket(int n, int k) { if(k >= n) return n; int l=1,h=n; bool front = true; while(l

17th June : C++ Solution ☝🏼

class Solution{ public: // Function to insert element into the queue void insert(queue &q, int k){ q.push(k); } int findFrequency(queue q, int k){// note we are not passing by reference // Your code here int ct=-1; while(!q.empty()){ if(q.front()==k) ct++; q.pop(); } return ct+1; } };

16th June : C++ Solution ☝🏼

#include <vector> #include <unordered_map> #include <algorithm> #include <cmath> using namespace std; class Solution { public: long long dp(int idx, int d, int m, vector<vector<long long>>& memo, const vector<int>& v, const unordered_map<int, int>& mn, const unordered_map<int, int>& mx) { if (idx >= m) return 0; if (memo[idx][d] != -1) return memo[idx][d]; int left = 0, right = 0; if (idx != 0) { left = mn.at(v[idx - 1]); right = mx.at(v[idx - 1]); } if (d == 1) swap(left, right); long long ans = 1e18; int ret1 = 0, ret2 = 0; if (idx == v.size() - 1) { ret1 = abs(mn.at(v[idx])); ret2 = abs(mx.at(v[idx])); } ans = min(ans, dp(idx + 1, 0, m, memo, v, mn, mx) + abs(mx.at(v[idx]) - left) + (mx.at(v[idx]) - mn.at(v[idx])) + ret1); ans = min(ans, dp(idx + 1, 1, m, memo, v, mn, mx) + abs(mn.at(v[idx]) - left) + (mx.at(v[idx]) - mn.at(v[idx])) + ret2); return memo[idx][d] = ans; } long long minTime(int n, vector<int>& locations, vector<int>& types) { vector<int> v; unordered_map<int, int> mn, mx; for (int i = 0; i < n; i++) { if (mn.count(types[i]) == 0) { mn[types[i]] = mx[types[i]] = locations[i]; v.push_back(types[i]); } else { mn[types[i]] = min(mn[types[i]], locations[i]); mx[types[i]] = max(mx[types[i]], locations[i]); } } int m = v.size(); sort(v.begin(), v.end()); vector<vector<long long>> memo(m + 5, vector<long long>(2, -1)); return dp(0, 0, m, memo, v, mn, mx); } };

15th June : C++ Solution ☝🏼

class Solution { public: string longestPalin (string S) { int n = S.size(); int anslen = 0; string ans = ""; for(int i = 0; i=0 && r anslen){ anslen = r-l+1; ans = S.substr(l, anslen); } l--; r++; } //even length l = i, r=i+1; while(S[l] == S[r] && l>=0 && r anslen){ anslen = r-l+1; ans = S.substr(l, anslen); } l--; r++; } } return ans; } };

14th June : C++ Solution ☝🏼

class Solution { public: long long maxDiamonds(int A[], int N, int K) { priority_queue<int, vector<int>> pq; for(int i=0; i<N; i++){ pq.push(A[i]); } long long ans = 0; while(K--){ int maxi = pq.top(); pq.pop(); ans+=maxi; pq.push(maxi/2); } return ans; } };

13th June : C++ Solution ☝🏼

class Solution{ public: vector kLargest(int arr[], int n, int k) { sort(arr,arr+n); vector ans; for(int i=n-1; i>=n-k;i--){ ans.push_back(arr[i]); } return ans; } };

12th June : C++ Solution ☝🏼

class Solution{ public: int cutRod(int price[], int n) { vector dp(n+1, 0); for(int i = 1; i<=n; i++) for(int idx = 0; idx

11th June : C++ Solution ☝🏼

class Solution{ public: void update(int a[], int n, int updates[], int k) { for(int i = 0; i < k; i++) a[updates[i]-1]++; for(int i = 1; i < n; i++){ a[i] += a[i - 1]; } } };

10th June : C++ Solution ☝🏼

class Solution { public: void Rearrange(int arr[], int n) { vector v; for(int i=0; i=0)v.push_back(arr[i]); for(int i=0; i

9th June : C++ Solution ☝🏼

class Solution { public: vectorfind_permutation(string s) { vector v; sort(s.begin(),s.end()); v.push_back(s); string s1=s; while(true) { next_permutation(s.begin(),s.end()); if(s==s1) break; v.push_back(s); } return v; } };