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Mr. BëArdÔ: def bfs(graph,c,t): s=1 n=len(graph)-1 dist=[] pred=[] color=[] q=[] count=0 for _ in range(len(graph)): dist.append(9999) pred.append(None) color.append('w') q.append(s) dist[s]=0 color[s]='g' while len(q)!=0: u=q.pop(0) if u==n: break count+=1 color[u]='b' for i in graph[u]: if color[i]=='w': q.append(i) color[i]='g' dist[i]=dist[u]+c pred[i]=u return dist[n] n,m,t,c=map(int,input().split()) graph=[[] for _ in range(n+1)] for _ in range(m): x,y=map(int,input().split()) graph[x].append(y) graph[y].append(x) time=bfs(graph,c,t) signal='g' signals=[None] for _ in range(t): signals.append('g') for i in range(t,time+1): if i==0: continue if (i//t)%2==0: signals.append('g') else: signals.append('r') for i in range(0,time,c): if signals[i]=='r': time+=(signals[i+1:].index('g')) print(time) Python accolie beautiful path Telegram- https://t.me/Coding_solution_0

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#include<stdio.h> #include<math.h> int isPerfectSquare(int number) { int iVar; float fVar; fVar=pow(number,1.0/3.0); iVar=(int)fVar; if(iVar==fVar) return number; else return 0; } int main() { int n; scanf(“%d”,&n); int arr[n]; int i; for(i = 0; i < n; i++) { scanf("%d",&arr[i]); } int count = 0; for(i = 0; i < n; i++) { if(isPerfectSquare(arr[i])) count++; } printf("%d",count); return 0; } E-Commerce Telegram- https://t.me/Coding_solution_0

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