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allcoding1_official

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تُعد قناة allcoding1_official (@allcoding1_official) في القطاع اللغوي الإنكليزية لاعباً نشطاً. يضم المجتمع حالياً 85 628 مشتركاً، محتلاً المرتبة 1 508 في فئة التكنولوجيات والتطبيقات والمرتبة 3 501 في منطقة الهند.

📊 مؤشرات الجمهور والحراك

منذ تأسيسه في невідомо، حقق المشروع نمواً سريعاً وجمع 85 628 مشتركاً.

بحسب آخر البيانات بتاريخ 21 يونيو, 2026، تحافظ القناة على نشاط مستقر. خلال آخر 30 يوماً تغيّر عدد الأعضاء بمقدار -1 434، وفي آخر 24 ساعة بمقدار -33، مع بقاء الوصول العام مرتفعاً.

  • حالة التحقق: غير موثّقة
  • معدل التفاعل (ER): يبلغ متوسط تفاعل الجمهور 3.09‎%. وخلال أول 24 ساعة من النشر يحصد المحتوى عادةً 0.73‎% من ردود الفعل نسبةً إلى إجمالي المشتركين.
  • وصول المنشورات: يحصل كل منشور على متوسط 2 645 مشاهدة. وخلال اليوم الأول يجمع عادةً 625 مشاهدة.
  • التفاعلات والاستجابة: يتفاعل الجمهور بانتظام؛ متوسط التفاعلات لكل منشور يبلغ 1.
  • الاهتمامات الموضوعية: يركز المحتوى على مواضيع رئيسية مثل dsa, stack, namaste, javascript, dev.

📝 الوصف وسياسة المحتوى

وصف القناة غير متوفر.

بفضل وتيرة التحديث المرتفعة (أحدث البيانات بتاريخ 22 يونيو, 2026) تحافظ القناة على حداثتها ومستوى وصول مرتفع. وتُظهر التحليلات تفاعلاً نشطاً من الجمهور، ما يجعلها نقطة تأثير مهمة ضمن فئة التكنولوجيات والتطبيقات.

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#include<bits/stdc++.h> using namespace std; int main() {     int n,c,d ;     cin>>n>>c>>d ;     int b[n],p[n],t[n] ;     for(int i=0;i<n;i++)         cin>>b[i]>>p[i]>>t[i] ;     vector<pair<int,int>>type_0,type_1 ;     for(int i=0;i<n;i++)     {         if(t[i]==0)         {             type_0.push_back({p[i],b[i]}) ;         }         else         {             type_1.push_back({p[i],b[i]}) ;         }     }     sort(type_0.begin(),type_0.end()) ;     sort(type_1.begin(),type_1.end()) ;     // One using coins and one using diamonds     int max_0=0,max_1=0 ;     int x=type_0.size() ;     int y=type_1.size() ;     for(int i=0;i<x;i++)     {         if(type_0[i].first<=c)             max_0=max(max_0,type_0[i].second) ;     }     for(int i=0;i<y;i++)     {         if(type_1[i].first<=d)             max_1=max(max_1,type_1[i].second) ;     }     int ans=0 ;     if(max_0&&max_1)         ans=max(ans,max_0+max_1) ;       // Both using coins     multiset<int>m;                             for(int i=0;i<x;i++)     {        m.insert(type_0[i].second) ;     }     int j=type_0.size()-1 ;     for(int i=0;i<x;i++)     {         if(j<=i)             break ;         auto it=m.find(type_0[i].second) ;         m.erase(it) ;         int flag=0 ;            while(j>i)         {             if(type_0[j].first+type_0[i].first<=c)             {                 flag=1 ;                 break ;             }             auto it=m.find(type_0[j].second) ;             m.erase(it) ;             j-- ;         }         if(flag==0)             break ;         if(m.size())         ans=max(ans,type_0[i].second+*m.rbegin()) ;       }     // Both using diamonds     m.clear() ;     for(int i=0;i<y;i++)     {        m.insert(type_1[i].second) ;     }      j=type_1.size()-1 ;     for(int i=0;i<y;i++)     {         if(j<=i)             break ;         auto it=m.find(type_1[i].second) ;         m.erase(it) ;         int flag=0 ;         while(j>i)         {             if(type_1[j].first+type_1[i].first<=d)             {                 flag=1 ;                 break ;             }             auto it=m.find(type_1[j].second) ;             m.erase(it) ;             j-- ;         }         if(flag==0)             break ;         if(m.size())         ans=max(ans,type_1[i].second+*m.rbegin()) ;     }     cout<<ans<<"\n" ;     return 0; } Uber

#include<bits/stdc++.h> using namespace std; string str, bad_string; struct node{     bool end_mark;     node *next[10];     node()     {         end_mark = false;         for(int i = 0; i<10; i++)             next[i] = NULL;     } }*root; bool add(string s) {     node *current = root;     for(int i = 0; i<s.size(); i++)     {         int nw = s[i] - 'a';         if(i == (s.size()-1) && current->next[nw] != NULL)             return false;         if(current->next[nw] == NULL)             current->next[nw] = new node();         current = current->next[nw];         if(current->end_mark)             return false;     }     current->end_mark = true;     return true; } int main() {     int i, N;     bool ok = true;     cin >> N;     root = new node();     for(i = 1; i<=N; i++)     {         cin >> str;         if(!ok)             continue;         ok = add(str);         if(!ok)             bad_string = str;     }     if(ok)         printf("GOOD SET\n");     else     {         printf("BAD SET\n");         cout << bad_string << endl;     } } Good Bad String Uber

#include <bits/stdc++.h> using namespace std; const int MOD = 1e9 + 7; long long solution(int n, vector<long long>& a, vector<long long>& b) {     long long ans = 0;     int minP = min_element(a.begin(), a.end()) - a.begin();     int minQ = min_element(b.begin(), b.end()) - b.begin();     for (int i = 0; i < n; i++) {         if (i == minP || i == minQ)             continue;         ans += min(a[minP] * b[i], b[minQ] * a[i]);         ans %= MOD;     }     if (minP != minQ) {         ans += a[minP] * b[minQ];         ans %= MOD;     }     return ans; }. professor code Uber

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#include #include #include using namespace std; int getMinTransactions(int n, vector&gt;&amp; debt) { &nbsp;&nbsp;&nbsp; unor
#include <vector> #include <unordered_map> #include <iostream> using namespace std; int getMinTransactions(int n, vector<vector<int>>& debt) {     unordered_map<int, int> balance     for (const auto& d : debt) {         balance[d[0]] -= d[2];         balance[d[1]] += d[2];     }         vector<int> transactions;     for (const auto& entry : balance) {         if (entry.second != 0) {             transactions.push_back(entry.second);         }     }     int count = 0;     int i = 0, j = transactions.size() - 1;     while (i < j) {         if (transactions[i] + transactions[j] == 0) {             count++;             i++;             j--;         } else if (transactions[i] + transactions[j] > 0) {             transactions[i] += transactions[j];             j--;             count++;         } else {             transactions[j] += transactions[i];             i++;             count++;         }     }     return count; } Transaction Simplification

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int solve(vector tc) { &nbsp;&nbsp;&nbsp; int n = tc.size(); &nbsp;&nbsp;&nbsp; vector p(n), s(n); &nbsp;&nbsp;&nbsp; p[0] =
int solve(vector tc) {     int n = tc.size();     vector p(n), s(n);     p[0] = tc[0];     for (int i = 1; i < n; ++i) {         p[i] = p[i - 1] + tc[i];     }     s[n - 1] = tc[n - 1];     for (int i = n - 2; i >= 0; --i) {         s[i] = s[i + 1] + tc[i];     }     int m = max(p[0], s[0]);     for (int i = 1; i < n; ++i) {         m = max(m, max(p[i], s[i]));     }     return m; } Amazon

#include #include #include using namespace std; long getkRepValue(string user_history, long k) { &nbsp;&nbsp;&nbsp; long n =
#include <iostream> #include <string> #include <unordered_map> using namespace std; long getkRepValue(string user_history, long k) {     long n = user_history.size();     unordered_map<char, long> count;     long left = 0, right = 0, ans = 0;     while (right < n) {         count[user_history[right]]++;         while (count[user_history[right]] >= k && left <= right) {             ans += n - right;             count[user_history[left]]--;             left++;         }         right++;     }     return ans; }  Machine learning Amazon

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class Message(object): def init(self, message: str, sender: int, receiver: int) -> None: self.message = message self.sender =
class Message(object):     def init(self, message: str, sender: int, receiver: int) -> None:         self.message = message         self.sender = sender         self.receiver = receiver     def str(self) -> str:         return self.message     def eq(self, other: object) -> bool:         if not isinstance(other, Message):             return False         return self.message == other.message Message Objects

#include <iostream> #include <sstream> #include <string> #include <vector> std::string stemmer(const std::string& text) {     std::stringstream ss(text);     std::string word;     std::vector<std::string> stemmed_words;     while (ss >> word) {         if (word.size() > 2 && (word.substr(word.size() - 2) == "ed" word.substr(word.size() - 2) == "ly" word.substr(word.size() - 3) == "ing")) {             word = word.substr(0, word.size() - 2);         }         if (word.size() > 8) {             word = word.substr(0, 8);         }         stemmed_words.push_back(word);     }     std::string result;     for (const std::string& stemmed_word : stemmed_words) {         result += stemmed_word + " ";     }     result.pop_back();     return result; } int main() {     std::string text = "an extremely dangerous dog is barking";     std::cout << stemmer(text) << std::endl;  // Output: "an extreme dangerou dog is bark"     return 0; } Suffix stripping stemmer

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heights = [int(i) for i in input().split()] freq_dict = {} for h in heights: if h in freq_dict: freq_dict[h] += 1 else: freq_
heights = [int(i) for i in input().split()] freq_dict = {} for h in heights: if h in freq_dict:   freq_dict[h] += 1 else:   freq_dict[h] = 1 for h in sorted(freq_dict): print(h, freq_dict[h])