Electrical Engg. By Ashish sir
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⭕ Attention
quiz schedule
Date :22.04.20
Non tech quiz : english gk+ grammar + computer
Time : @t 11.00 am
At 12.30 pm : test on previous year question papers of JE/ AE exam
No.Of questions..... .30
At 9.00 pm. : marathi grammar quiz
No.of questions : 30
📌All questions are important in next quiz
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Shaikh Najiya @eeletsrock1021
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Listen everyone ....
Aaj ka quiz bahut important hai.....
Attend kro sabhi .....
Previous year exam k questions hai sabhi. ......
Don't miss today's quiz
⭕ Attention
quiz schedule
Date :22.04.20
Non tech quiz : english gk+ grammar + computer
Time : @t 11.00 am
At 12.30 pm : quiz test of electrical all mix topic
No.Of questions..... .30
At 9.00 pm. : marathi grammar quiz
No.of questions : 30
📌All questions are important in next quiz
📌Don't miss the quiz
Shaikh Najiya @eeletsrock1021
https://t.me/eeletsrock1021
💐💐💐💐💐💐💐💐💐💐
Electrical students technical hi nahi.....Non technical me bhi top kar sakte u can prove this. 👍👍👍👍
Jo electrical k is group k student upsc group me...Ans.de rhe...Top me aa rhe...Aap sabhi ko congrats
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⭕ Attention
quiz schedule
Date :21.04.20
At 12.30 pm : quiz test of electrical all mix topic
No.Of questions..... .30
At 9.00 pm. : marathi grammar quiz
No.of questions : 30
📌All questions are important in next quiz
📌Don't miss the quiz
Shaikh Najiya @eeletsrock1021
https://t.me/eeletsrock1021
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In this group abhi Gk english ..And..English grammar ka quiz le rhi hun...Join this group now
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⭕ Attention
quiz schedule
Date :21.04.20
At 12.30 pm : quiz test of electrical all mix topic
No.Of questions..... .30
All questions are important join quiz Fast
Electrical technical quiz
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If the power factor is high, then the consumer maximum demands
1. Increase
2. Decrease✔️
3. Becomes zero
4. Remains Constant
Explanation
Kva=kw/cos$
Now considering the above equation, for a given requirement of kW, the value of kVA reduces if we have good power factor.
Let us understand with an example,
Consider a case wherein we need 100 kW as output. Now
Case1: for a power factor of 0.8
We would require 120kva for fulfilling the required demand. (Calculated as per equation is written above)
Case2: power factor of 1 (unity)
Here, the value of kVA required is 100 kVA. Which is less than the previous case. This indicates that the kVA demand decreases if power factor of my equipment increases.
. For painful shock what is the range of electric shock current at 50 Hertz?
1. 0-1 mA
2. 3-5 mA✔️
3. 0-3 mA
4. 5- 10 mA
Explanation
• The damage caused by electric shock depends on the current flowing through the body — 1 mA can be felt; 5 mA is painful.
• Above 15 mA, a person loses muscle control, and 70 mA can be fatal.”
• The amount of damage done by the electric shock depends not only on the magnitude of the current, but it also on which portions of the body that the electric current is flowing through. The reason for this is that different parts of the body have different resistances, which can lead to an increase in current
A 10 pole 25 Hz alternator is directly coupled to and is driven by 60 Hz synchronous motor then the number of poles in a synchronous motor is?
1. 24 poles ✔️
2. 48 poles
3. 12 Poles
4. None of the above
Explanation
Number of poles of alternator Pa = 10
F = 25 Hz (alternator)
F = 60 Hz (motor)
Then the number of poles of motor Pm =?
Since synchronous motor is directly coupled hence
Synchronous speed of an alternator = Synchronous speed of the motor
(120 x 25)/10 = (120 x 60)/ Pm
Pm = 24
In a pure inductive circuit if the supply frequency is reduced to half the current will?
1. Be four times as high
2. Be doubled
3. Be reduced to half
4. Be reduced to one fourth
Explanation
The amplitude of the current in a pure inductive circuit is given by
Im = Vm/ωl
And ω = 2πf
Im = Vm/2πfl
Im ∝ 1/f
Hence, when the frequency is halved, the amplitude of the current is doubled in a pure inductive circuit.
How much energy is stored in a 100 mH inductance when a current of 1A is flowing through it?
1. 5.0 J
2. 0.05
3. 0.5 J
4. 0.005 J
Explanation
The energy stored in the magnetic field of an inductor can be expressed as
E = 1/2 L I2
where
E = energy stored (joules, J)
L = inductance (henrys, H)
I = current (amps, A)
1/2(100 x 10-3 x 1)
50 x 10-3 J
0.05 J
Resistor values can be known by the color band.
0 black
1 brown
2 red
3 orange
4 yellow
5 green
6 blue
7 violet
8 grey
9 white
First color = digit
Second color=digit
Third color= power of ten
Fourth color =tolerance
Now in the given question 50 × 100 ± 2%
5 = Green
0 = Black
100 = Black
± 2% = Red
What will be the color-coding of a resistor when the resistance of the resistor is 50 + 2% ohms?
1. Green-Black-Brown-Red
2. Green-Black-Black-Brown
3. Yellow-Brown-Black-Red
4. Green-Black-Black-Red✓
