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Dear Petroleum Engineers,
𝐑𝐌𝐒 𝐆𝐀𝐓𝐄 𝐀𝐏𝐓𝐈𝐓𝐔𝐃𝐄 𝐓𝐄𝐒𝐓-1 𝐈𝐒 𝐎𝐍𝐋𝐈𝐍𝐄 𝐍𝐎𝐖
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#MathsSolution
Correct answer is GIVEN,
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There will be 3 cases.
Case 1 : Ball is chosen from 1st bag.
Probability of green ball from 1st bag = (1/3)×(2/6)
= 1/9
Case 2 : Ball is chosen from 2nd bag.
Probability of green ball from 2nd bag = (1/3)×(5/9)
= 5/27
Case 3 : Ball is chosen from 3rd bag.
Probability of green ball from 3rd bag
= (1/3)×(3/9)
= 1/9
So required probability
= 1/9 + 5/27 + 1/9
= 11/27
Dear all, If you have any kind of doubts regarding questions and concept, you can direct message me, open search in telegram @Acepetroadmin and direct message me your doubts.
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