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Answer for the minimum pluses in python 3
all_ans = {}
def min_pulses(A, target):
if (A, target) in all_ans:
return all_ans[(A, target)]
if len(A) == 0:
if target != 0:
return -1
else:
return 0
while len(A) > 0 and A[0] == '0':
A = A[1:]
if len(A) == 0 and target == 0:
return 1
if target < 0:
return -1
i = 1
ans = float('inf')# initializing ans to infinite number so that min can be update
while i <= 5 and i <=len(A):
curr_num = A[:i]
curr_ans = min_pulses(A[i:], target - int(curr_num))
if curr_ans >= 0:
ans = min(1 + curr_ans, ans)
i += 1
if ans == float('inf'):
ans = -1
all_ans[(A,target)] = ans
return ans
equation = input().split('=')
A = equation[0]
target = int(equation[1])
groups = min_pulses(A, target)
if groups < 0:
print(-1)
else:
print(groups - 1)
does anyone got information about capgemini drive from tpo?
Please share it here
It would be really helpful
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